nup i havnt got the correct answer but its liek a follow on question...
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lol im confused... :S
umm its 1/(3-x)^2
are u guys using that formula:
integral of (ax+b)^n = [(ax+b)^n+1]/(n+1)a
??
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hey guys
ive gotta mental blank...:confused:
how do u integrate:
1/(3-x)^2
thanks heaps for the help!! :)
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Re: Studying during hols
hey
haha goodluck for the half yearlies.. must suck dont even get a hol ><"
hmm yeh i guess i could try those ideas out xD
and lol 12hrs a day ..><"
thanks! =)