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Have you made any progress so far? If yes, please let us know what you have and specify which part you're having trouble with? If not, have you learned differentiation yet?

(I haven't done chem in years, so don't quote me on this.) You don't have to memorise them. But it's good to know a few frequently used ones. As in you shouldn't 'memorise' them like memorising English essays(although many people are against this as well), instead you should get to know them...

+1 In the HSC, they wouldn't give a question like this(from a textbook exercise) : Instead, in the HSC you can always work it out from the standard potentials table, as InteGrand said actually you do get HSC questions like this (2011HSC):

I think what he means is that for a given f(x), graph the primitive function F(x). Then you always have a family of curves(F(x)) having the same gradient. For example, if given a graph like y=2x, then its primitive could be y=x^2(like the above diagram, backwards), but y=x^2+1 , y=x^2- pi ...

here we have y=x^2 and its derivative y'=2x (generally the equation of the function will NOT be given, but let's look at this simple example to understand what's actually happening) you can choose any point on f(x), draw the tangent , and find out its rise and run (here I've used numbers...

yes, just note that the point of inflexion of f(x) ----> MAX or MIN (depending on the sign of gradient of f(x)) of f'(x) In your question, it is MIN because the slope is most NEGATIVE at that point. Remember that derivative function f'(x) simply represents the gradient of f(x), and gradient...

Either option is fine because they are equivalent forms of the same thing, actually you can see both appearing in BOSTES solutions. But I personally suggest to leave it in the gradient-intercept form y=mx+b unless the question explicitly asks for the general form, because normally the way...

re: HSC Physics Marathon Archive Also what exactly are Newton's Laws of Motion? in particular for HSC physics It sounds 'trivial' but I guess most of us do not really know what they actually are.

re: HSC Physics Marathon Archive What do you think of the notes from the marking centre, which states: I just fail to see how we can use 2 or all 3 of Newton's Laws of Motion if no energy from the engine is involved/should be mentioned. After leaving the lunar orbit, worked is done to put...

re: HSC Physics Marathon Archive you mean change in momentum ? Impluse can be seen as (or causes) change in momentum: http://en.wikipedia.org/wiki/Impulse_(physics) In the case where F is constant, we have: http://www.grc.nasa.gov/WWW/k-12/airplane/newton2.html Coming back to the...

re: HSC Physics Marathon Archive Not sure whether Newton's 1st law is relevant. But the version above seems rather ambiguous. Then again, Newton's laws of motion are quite tricky. Up until 2nd year uni, I still didn't quite understand Newton's 2nd Law.

re: HSC Physics Marathon Archive I am not sure whether it's Jim Lovell or Tom Hanks the one who said that. I have this doubt because all the sites with that particular quote(or the ones I've seen) are referring to the movie. But anyways, from what I understand, the spacecraft did not get hit...

I think the impact on the school's assessment marks is also taken into consideration. At my school ,one year they had way too many 4u English students and they did not perform very well in the HSC. And then for the year after that, the English head teacher decided to have a class size limit.

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if your teacher "circled the coordinate", I think( just taking a wild guess) what you mean is taking the reciprocal like y=\frac{1}{f(x)} , not the inverse y= f^{-1}(x) For example, look at this question from 2014 HSC. In part (ii) you are gonna have an open circle because the function f(x)...

I think one of the issues here is not having that sense of satisfaction of being able to solve all(or most) of the questions. And getting a relatively low raw mark in 4u (as opposed to the 90's in 2u and 3u) does seem disappointing. However as they've mentioned above, you do have to take into...

whenever you use t-results , you ALWAYS have to check that if x= pi/2 is a solution precisely because tan(pi/2) is undefined (as MethewYan mentioned before) alternatively the argument using 'general solutions' might be easier

F'(2)=F"(2)=0 does not necessary imply A HORIZONTAL POINT OF INFLEXION You need to verify there's a change of concavity i.e. F''(x) has opposite signs to either side of x=2 e.g. for f(x)= x^3 f''(0)=f'(0)=0 ALSO, f''(x)>0 for x>0 , f''(x)<0 for x<0 ====> f'' has opposite signs...

If I were you , I wouldn't be worried about 'scaling' (if it exists) what I can say from experience is that you should take units you like and/or you need the "need" part is probably easier to explain: for your adv sci degree , if your major does not require a lot of maths background...

if the question is just finding the integral, then integral= area of the semicircle