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Hey lets insult someone for using a superior platform and trying to tell others about it. Hey that's logical. Superior in some ways, inferior in others. I_F

A polynomial P(x) is odd, i.e. P(-x) = - P(x) 1. prove that P(0) = 0 and hence show that p(x) is divisible by x. If P(-x) = - P(x), when x = 0, P(0) must equal - P(0) The only time when a number equals its negative is when the number is zero, i.e. 0 = -0. For divisibility, when you...

The workload isn't too dissimilar to Year 11 at the moment - it's still quite relaxed. We've got assessments coming up, but they're well spaced, so I have time to concentrate on each one. Not too bad at the moment, but we'll see what it's like next year... I_F

No problemo. :) I_F

He could, but that usually means finding f''(x) anyway to sketch f'(x) I_F

Horizontal asymptote is at 0 From the limit as x -> infinity, the curve approaches 0 as it goes to infinity, yes, but the curve is actually 0 when x is -1 or -3, so it's not an asymptote per se. Unless you want to start debating about the definition of "asymptote" (stupid maths teacher...)...

Open up AIM. Hit "Setup", then go to the "Talk" tab. There's a button there labelled sounds. Click on that and uncheck all the options to turn the sound off. I_F

Given f(x)=(x2-4x+3)/(x-2)3 i) find the x and y intercepts (2 marks) y-intercept: -3/2 x-intercepts: -1, -3 ii) show that f'(x)=(-x2+4x-1)/(x-2)4 (3 marks) f(x)=(x2-4x+3)/(x-2)3 f'(x) = (vu' - uv')/v2 = [(x-2)3(2x - 4) - (x2-4x+3).3(x-2)2]/(x-2)6 = (x-2)2(2x2 - 4x - 4x +...

There is a very nice presentation located here: http://www.mhhe.com/physsci/chemistry/essentialchemistry/flash/galvan5.swf] on the Daniel Cell. You'll need Macromedia Flash to view the presentation. :) I_F

If an AGP X1800 comes out, I would consider it too provided it's reasonably priced. While my CPU might bottleneck (especially since it's a Pentium 4), as long as the game runs smoothly with some eye candy I will be happy. What's the point of 100fps+ if you can't see it anyway (except bragging...

Just that it was highly unfortunate for ATi that nVidia suddenly managed to pull the 512MB GTX out of nowhere. I know you like anandtech.com, and they had a very nice article link up the other day on how nVidia created the GeForce 7800 GTX 512 MB. Apparently, nVidia was actually sitting on...

A = 20,000 r = 0.11 n = 6 A = P(1 + r/100)n P = A/(1 + r/100)n P = 20000(1 + 11/100)6 Solve from there. a) M = 30000 x 1.1530 x .115/(1.11530 - 1) = $9065.90 per year I'll work out the others later if I get time. I_F

I'm taking a 'wait and see' approach to this. R520 was supposed to be an uber l33t nVidia killer, and it disappointed. You still can't reasonably expect to get hold of an x1800XT since supply is so low. x1800XT CrossFire cards aren't due to begin mass production for another month, and ATi faces...

I don't think this will greatly affect sales. If you don't upgrade your motherboard, odds are you haven't upgraded your CPU, and with many games CPU limited these days, it's better to upgrade all at once. AGP's well on its way out. I_F

To do this question, add up the energy used to break all the broken bonds, then subtract the energy gained from creating the new bonds. So: CH3CH2OH (l) + 3O2 (g) -> 2CO2 (g) + 3H2O (l) Bonds broken: 5 x C-H -> 2060 kJ 3 x O=O -> 1488 kJ 1 x C-C -> 348 kJ 1 x C-O -> 360 kJ 1 x...

The other prac wouldn't be the Physics one where you run an electric coil through water in a styrofoam cup to measure the electrical power, would it? Well, we used a styrofoam cup, anyway. I_F

Try Wikipedia's entry on polystyrene here. :) I_F

Last year, my school had our SC results on our last day, so I'd expect your results in 3-4 weeks time. :) I_F

Firstly, welcome. :) And yes, HSC assessments generally start Term 4 of your Prelim year. I've just had my first Maths assessment, I have another one next week with a Chem assessment, then English, and Physics to round the term off. It's the last year now and each assessment counts. Better...

Differentiate x2=4ay i) with respect to x. ii) with respect to y. i) x2=4ay Therefore y = x2/4a Therefore, assuming a is a constant, dy/dx = 2x/4a = x/2a ii) x2=4ay Therefore x = √4ay = 2√(ay) = 2(ay)1/2 Assuming a is a constant, dx/dy = 2(a/2√y) = a/√y...