NO2(g) + O3(g) → NO2(g) + O2(g)
0.66 g of NO is reacted with 0.72 g of O3.
n = m/M
The molar mass of NO is 14 + 16 = 30 g, therefore we have 0.66/30 = 0.022 moles. (Note that I didn't round off)
The molar mass of O3 is 16 x 3 = 48 g, therefore we have 0.72/48 = 0.015 moles. (Note that I...