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  1. KFunk

    Polynomial Question

    Hey guys, this is a question which Slide Rule passed on to me. It's not very difficult but I found it interesting for some reason so I thought I'd share it: Show that the remainder when the polynomial P(x) is divided by (x - a)<sup>2</sup> is P'(a)x + P(a) - a.P'(a)
  2. KFunk

    Totally disgusted by the American arrogance and comments on Australian med schools!

    That kind of attitude is just as bad as the arrogance you are criticizing.
  3. KFunk

    Hey guys

    I've done pretty much all past papers back to 1990 so I'm good in that department. I just need to iron out my weaknesses - conics and geometry in particular. My ultimate goal is to get a mark in the 100's, I've been able to get that in several past papers but I just can't be confident about my...
  4. KFunk

    Best Topic in 4 unit

    Some of the harder complex number excercises can be cool (e.g. 1993 Q8). There is a small amount of interesting harder polynomial stuff too, oh and also the unusual combinatorics questions.
  5. KFunk

    trig question

    I geuss the way I'm looking at it is that all of his operations are reversible, so a proof in one direction implies both.
  6. KFunk

    trig question

    Never mind, you've explained it enough as is. I think it's an agree to disagree situation :p.
  7. KFunk

    trig question

    There should be some statement you can make to justify a backwards proof. It feels like this is a grammatical (not a mathematical) issue. It's like the way good is favoured over bad, first before last and over before under ---> likewise forwards is favoured over backwards. In conclusion: I hold...
  8. KFunk

    trig question

    Hmm, thanks for the explanation. I still think one could argue, however, that there's nothing wrong with using such logic when the issues you describe are 'trivial' (as you put it). If all the operations are perfectly reversible the p implies q also necesitates q implies p , does it not (correct...
  9. KFunk

    Challenging probability question

    Given that you're online at the moment I thought I'd ask, what's your crafty method?
  10. KFunk

    When are Monash interviews coming out?

    I got an interview offer in the post today (UMAT score = 196).
  11. KFunk

    Chem vs Phys

    Physics is far superior to chemistry (p.s. I am biased).
  12. KFunk

    trig question

    i think I might get it. Is it the difference between say: 'a' represents sin<sup>2</sup>&theta;+cos<sup>2</sup>&theta; = 1 'b' represents statement x<sup>2</sup> + y<sup>2</sup> = 1 where if a is true then not(a) is untrue but if b is true then that does not logically imply that...
  13. KFunk

    trig question

    I think I've missed what the logical slip is with my case 1. For the sake of argument let q be something like sin<sup>2</sup>&theta;+cos<sup>2</sup>&theta; = 1 which is, at least in the MX1 forum, an irrefutable truth.
  14. KFunk

    Complex locus Q

    For the range of the values of t i think this might be a way to go about it: We know that 2t = 2x ---> t=x Using our locus definition we know that (-1 - &radic;2) &le; x &le; (-1 + &radic;2), i.e. the domain of the circle, so I would assume that - (-1 - &radic;2) &le; t &le; (-1 +...
  15. KFunk

    Complex locus Q

    Use the definition |z| = &radic;(x<sup>2</sup> + y<sup>2</sup>) to give you: x<sup>2</sup> + y<sup>2</sup> - 2i(x + iy) + 2t(1+i) = 0 x<sup>2</sup> + y<sup>2</sup> - 2ix + 2y + 2t + 2ti = 0 Equating real parts we get: x<sup>2</sup> + y<sup>2</sup> + 2y = -2t ......(1) Equating...
  16. KFunk

    IntegrationInduction

    No probs 10 chars
  17. KFunk

    IntegrationInduction

    Skipping over the n=1 case (and letting S<sub>n</sub> represent the proposition), assume true for n= k so: &int; (0 to 1) x<sup>k</sup>e<sup>x</sup> dx = a<sub>k</sub> + b<sub>k</sub>e ...(1) ... then when n= k+1 &int; (0 to 1) x<sup>k+1</sup>e<sup>x</sup> dx =...
  18. KFunk

    IntegrationInduction

    For that bit you know that 1 &le; e<sup>x</sup> &le; e < 3 (for 0 < x < 1) hence: e<sup>x</sup> < 3 x<sup>&alpha;</sup>e<sup>x</sup> &le; 3x<sup>&alpha;</sup> (since x &ge; 0) &there4; &int; (0 to 1) x<sup>&alpha;</sup>e<sup>x</sup> dx < 3&int; (0 to 1) x<sup>&alpha;</sup> dx =...
  19. KFunk

    trig question

    I've never fully understood the issues with the direction of a proof. It seems to be an issue of semantics 'cause both are logically saying the same thing (aren't they?): Case 1: Assume p. p implies q. q is true, &there4; p is true. (as acmillan did) Case 2: q is true. q implies p...
  20. KFunk

    harder inequality proves

    Are you sure you wrote the question out correctly? If you take an example: 1<sup>3</sup> + 2<sup>3</sup> + 3<sup>3</sup> + 4<sup>3</sup> + 5<sup>3</sup> = 225 I figured there were two ways to read what you wrote: (n<sup>4</sup>)/3 = 5<sup>4</sup>/3 = 208 1/3 or n<sup>4/3</sup> =...
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