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Which is why I managed such a wonderfully incorrect (possibly) answer... :p Close, it's bootsy collins: one of the world's funkiest bass players. He did a fair bit of co-writing with Clinton in Parliament but then the offshoot 'Bootsy's rubber band' developed.

1. y = 4/( 7x²) + (3/7) (7x²)(y - 3/7) = 4 x² = 4/(7y - 3) V = ∫ πx² dy from y= 1 to 4 V = π∫ 4/(7y - 3) dy = π[ 4/7.ln(7y - 3)] from 1 to 4 = 4π/7. ln(25/4) L 2. a) V = 4π/7. ln{[7(H+1)-3]/4} L since when...

Nah, he has better things to do than to come onto these forums.

I didn't know that you were allowed to give weightings over 40%. Fourty is bad enough but 45-50 is huge!

4U Mathematics - 40% ... top that :p . . . . smallest - English = 25%

a) The maximum height is achieved by the ball when dy/dt (vertical velocity) = 0. This makes logical sense since when the vertical velocity is zero it aint going to go any higher. 0 = Vsinθ - gt ----> t₀ = Vsinθ/g use this in conjunction with the function for...

a = d(1/2v²)/dt = sin²x 1/2v² = ∫ sin²x dx 1/2v² = 1/2∫ 1 - cos2x dx 1/2v² = x/2 - 1/4sin2x + c , but x=0 when v=1 so: 1/2 = c ∴ v² = x - 1/2sin2x + 1

I suspect he's being ironic ;).

Cos is an even function so: F(x) = cosx ---> F(x) = F(-x) so cos(2Θ ) = cos(-2Θ )

Starting next week: mon - English 1 tue - Ext. 2 Maths wed - UMAT (dammit) thu - English 2 fri - Physics mon - Chem then Ext. 1 English fri- Ext. 1 Maths

I assume you're talking about ∫ (lnx)²dx in which case use integration by parts where: u = (lnx)² , u' = 2lnx/x v'= 1 , v=x ∫ 1.(lnx)²dx = x(lnx)² - 2∫ lnx dx (then use integration by parts again on lnx where u = lnx) =...

Derive it, it doesn't take too long.

Very prompt. Cheers mate.

Do you have the second page of le volumes/recursion sheet? I'm curious to see the question that goes with that answer.

Haha, I appreciate it, but my name really shouldn't be on that list of consideration :p. I really do enjoy the stuff but I don't think I have much innate talent for the subject. I'd put my vote with who_loves_maths largely because he attacks a question from every possible angle, very...

Partying, playing music, chilling out with my friends, chilling out in my hammock, reading, learning to drive and all the other things which have taken an unfortunate backseat during this HSC year.

I'd expect to get in the 95+ range (going on statistics) but it's 99+ that I'm really striving for.

Word, I've been doing about 3-4 hours a day on average. [My trials are in week 2]

I don't have school on that day anyway 'cause it's in the middle of my trials. It's a tad annoying to have it sandwiched between ext. 2 math and english paper 2 but at least I'm in exam mode I geuss.

Well, if you can grow a few inches and sit my chem trial, then we've got something of a deal going on here.