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Most of my subjects only have ~30% weigh for trials. I wish they were like 40% :'( What are yours?

all of them

I will create a drug that accelerates the body's restoring functions during sleep so that you only need to sleep for 30 minutes and then you're brand new!

Nope, quite the opposite. Really took the holiday as a chance to "come down" and completely relax. Now that I've touched work its like a drug!

Replying chronologically: a) Yeah I know of your top method (most common way I think to solve the question but I was just exploring this "4u" method) b) "The dQ and the dt are actually legitimate objects called differential forms" - this is something that sounds very interesting :) I guess I'll...

Thanks for 1. Makes more sense that way. But for 2 I still disagree and my problem is the way I view the integral operation. For dy = dx, I (would) treat dy,dx as integrands and then integrate them both with respect to something common. E.g. integral (dy).dt = integral (dx).dt But this...

I find higher level maths (algebra) to lack common sense to me; instead becoming sought of a rote process. My foundations start to break down. e.g. For growth and decay (from 3U), finding the equation of Q given dQ/dt = kQ So, dQ/kQ = dt ---------(1) integral (dQ/kQ) = integral (dt)...

Almost 3 exams on 3 consecutive days. :( No time to relax

I think this is what many lost english students, including myself, needed to get back on track. Thank you!

Isn't your hsc in 2015?

I don't remember the film well but I think Deckard was only assigned to kill the escaped replicants. He also says to Rachael that replicants are a benefit or a hazard - and if hazard then a problem. So Deckard was sent to Tyrell Corporation not to kill nexus 6 replicants but test technology on...

use coefficient-root relationships (& complex conjugate root thereom)

I think you misunderstand the definition of voltage. Voltage is the electrical potential difference between two points. If a power supply supplies 10V, then that means across the entire circuit (from one terminal of the power supply to the other), there is 10 volts of difference. It must then...

How do you know that :L

All you need to know is that it will produce a shifted interference pattern (after rotating 90 deg). You're right in the sense that the same interference pattern is produced however this new interference pattern looks shifted. If you want to understand why, then I suggest looking into Thomas...

Well it didn't really help when you derived P = IV and then the next line stated Ploss = I^2R, completely unanswering the question. So I just buckled down and figured it out myself 20 minutes later.

if anything, markers think you can't read the bloody question and just flop around

Initially: say beam A was affected by the aether wind and beam B (perpendicular to aether wind) was not. This will produce a certain interference pattern. After apparatus rotated 90 deg: beam A is now unaffected by aether wind whereas B now is (due to their directions relative to the aether wind...

Yep, this was what I was going to say to EpaX. The V in P = IV is different to the V in V = IR. By subbing in the voltage drop V = IR across the transmission line into P = IV, you are effectively calculating the energy "drop" (loss) across that line.

Yeah this was my initial question but no one answered it (satisfactorily). I have a solution but I'll tell you after school today.