IF x is an integer, then it can be odd or even
Suppose x is odd, then there exists an integer M such that x = 2M + 1
x=\left \lfloor \frac{2M+1}{2} \right \rfloor + \left \lceil \frac{2M+1}{2} \right \rceil
= \left \lfloor M+\frac{1}{2} \right \rfloor + \left \lceil M + \frac{1}{2}\right...