You got the equation of a normal at
x+py=ap³ + 2ap
subbing in the point (0,ka)
k = p² +2
p² = k-2
Since k>2
p² > 2
therefore there's 2 solutions, so 2 normals
EDIT: Looking at trebla's solutions, I don't actually see why there's only 2, it seems as though there is 3...I'd probably test the...
If questions start to get a bit tricky, don't be afraid to try draw out an interpretation.
Do LOTS of questions so you'll be ready for anything when a test comes
Really know your definitions like PS/PM=e; this will allow you to solve bisector questions more easily
If you really don't think you can improve then it's best that you do. I'm just thinking though, if the other girl is averaging 100%, then maybe that would scale you up...or could be the other way and you scale her down.
My suggestion is if you drop, focus on Chem and English cause they seem to...
A thesis is your understanding of the texts you're studying, the BoS doesn't want you to copy someone else's thesis they want to see how well you've developed the ability to find your own understanding.
My thesis was that conflicting perspectives was a tool used by the composer to manipulate...
A text is a PRODUCT of those values and those values are the issues relevant in the time it was written (i.e. the context). Values can be anything from pro-feminists to scientific endeavours, for example, a value in Frankenstein was the role of playing God and scientific discovery such as...
How complicated do you want your approach to be? Reading that made my head spin, keep your approach simple and concise, you're examined on how well you understand the text not how verbose you can be
Also how is your assessment Module A if you say you're sitting HSC in 2012 (In your signature)?
^ that's a good point, CO2 dissolves in water so naturally, all rain that falls has a slight acidity to it due to H2CO3 presence, so you'd expect pH of around 3-5 and I have seen this in exams
I got (q+s+1)²-r² which is equivalent but by first finding the equation which has roots (1-α²)(1-β²)(1-γ²)(1-δ²)
I like your method of finding products of roots but could you explain how you got from
HERE
=(1-α)(1-β)(1-γ)(1-δ)(1+α)(1+β)(1+γ)(1+δ)
TO
=(1+q+r+s)(1+q-r+s)
THERE?
Cheers