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  1. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon Is there a formal proof for that?? If 'c' is a constant independent of x, then you can just bring it out of the integral
  2. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon lol that's a very articulate proof
  3. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon How wouldyou prove that it's the same besides using substitution: u = pi/2 - x?
  4. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon Ah that's cool Thanks
  5. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon Why is I = int 0 to pi/2 ln(sinx)dx = int 0 to pi/2 ln(sin2x) dx ?
  6. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon I've seen people do it by using int f(pi/2 - x) = int f(x) giving I = int 0 to pi/2 of ln(costheta) dtheta Then adding, giving 2I = int 0 to pi/2 of ln(sin2theta) - ln2 dtheta Then using u = 2theta, 2I = int 0 to pi of ln(sinu) - ln2 du And then they...
  7. kawaiipotato

    Jrahs q9

    Ahh, so that's why I got theta to be greater than pi radians?
  8. kawaiipotato

    Jrahs q9

    Thanks But the answer is A. It didn't have to go through the centre. And also, was just wondering why I got the result I did as stated in the OP. edit: it was B so ur correct
  9. kawaiipotato

    Jrahs q9

    Theta is the one at the centre facing 5y
  10. kawaiipotato

    Jrahs q9

    community.boredofstudies.org/attachments/13/mathematics-extension-1/30632d1404894953-ruse-2013-trial-solutions-2013-jrah-extn1-trial.pdf Q9 Firstly, I use 2pi*r = circumference = 9y Gives me r = 9y/2pi Then Constructing a chord to complete the triangle, I then construct the radius from the...
  11. kawaiipotato

    HSC 2015 MX2 Marathon (archive)

    Re: HSC 2015 4U Marathon Let u = pi/2 - x for both integrals LHS integral = int from -pi/2 to pi/2 of cos^8 x dx > 0 as it is even. RHS integral = int from -pi/2 to pi/2 of sin(4pi - 8x) = -sin8x dx = 0 as it is odd Holds true
  12. kawaiipotato

    HSC 2015 MX2 Marathon (archive)

    Re: HSC 2015 4U Marathon So like a conjugate bar for complex numbers?
  13. kawaiipotato

    HSC 2015 Maths Marathon (archive)

    Re: HSC 2015 2U Marathon oh lol thanks. don't know why I only added it
  14. kawaiipotato

    HSC 2015 Maths Marathon (archive)

    Re: HSC 2015 2U Marathon How did you know f(x) was linear? It could have been something like a cubic and the x^3 could just cancel each other out edit: nevermind, the coefficients are different so there's no way x^3 could cancel out. Wondering if there's an alternative method to this question...
  15. kawaiipotato

    HSC 2015 MX2 Marathon (archive)

    Re: HSC 2015 4U Marathon $ Let a number be in the form: $ a_n a_{n-1} ... a_1 a_0 $ where $ a_n $ is the 'n'th digit $ a_n a_{n-1} ... a_1 a_0 = a_0 + 10*a_1 + 100*a_2 + ... + 10^{n-1}a_{n-1} + 10^{n}a_{n} = a_0 + (9+1)a_2 + ... + (9+1)^{n-1}a_{n-1} + (9+1)^{n}a_{n} = a_0 + (9+1)a_2 +...
  16. kawaiipotato

    HSC 2015 Maths Marathon (archive)

    Re: HSC 2015 2U Marathon Let y = 3^x Eqn turns into y^2 + 2y - 15 = 0 Solve as a quadratic for y And then equate to 3^x Reject any negative y values by noting that 3^x > 0 for all real x
  17. kawaiipotato

    2015 Hurlstone Trial M/C Help

    oh i was in your truongs class before
  18. kawaiipotato

    2001 cutoffs

    Would anyone who's done it or experienced the paper have an idea of what the cutoff for e4 and/or state rank is? Thanks
  19. kawaiipotato

    2015 Hurlstone Trial M/C Help

    lol random advertisement to an instagram on a math thread on boredofstudies
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