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  1. kawaiipotato

    Graphing the derivative HSC question

    On the most left, f(x) appears to be increasing, that is, f'(x) >0. The concavity of f (x) is also negative, so f''(x) <0. That means for the f'(x) curve, the derivative (ie. The gradient) of that curve is also negative since f"(x)<0. So we can say that the f '(x) starts positive (above the x...
  2. kawaiipotato

    Extension 2 limiting sum problem with a sequnce

    Where did you get this question from?
  3. kawaiipotato

    Diagrams for the Solvay Process and Contact Process

    Thanks. My teacher said we should memorise them but I have yet to see a HSC question asking for it specifically.
  4. kawaiipotato

    Diagrams for the Solvay Process and Contact Process

    Do we need to memorise both diagrams?
  5. kawaiipotato

    stupid shit you've done in class

    Not that i can remember but i will post if i do
  6. kawaiipotato

    stupid shit you've done in class

    Hahah, i hope you didn't do the ethanol one on purpose
  7. kawaiipotato

    stupid shit you've done in class

    Dude what did your teachers say..? Also do you laugh whenever a chem exam asks for safety precautions for an experiment? Lol
  8. kawaiipotato

    Monster.

    Curious for the solution. I tried it but I realised can't the man just change directions during his path?
  9. kawaiipotato

    3 series questions

    imgur.com/a/vbwwR Check q20 tho. not sure
  10. kawaiipotato

    HSC 2015 Maths Marathon (archive)

    Re: HSC 2015 2U Marathon let y = f(x) be an even function So, y = f(x) = f(-x) Differentiating wrt. x, dy/dx = f'(x) = f'(-x) * d(-x)/dx f'(x) = -f'(-x) which is odd
  11. kawaiipotato

    HSC 2015 MX2 Marathon (archive)

    Re: HSC 2015 4U Marathon $ Consider, $ \cos \frac{A-B}{2} - \sin \frac{C}{2} = \cos \frac{A-B}{2} - \sin \frac{180 - A - B}{2} ( $ since $ A+B+C = 180 ($ angle sum of a triangle $ ) ) = \cos \frac{A-B}{2} - \sin(90 - \frac{A+B}{2}) = \cos \frac{A-B}{2} - \cos \frac{A+B}{2} = 2...
  12. kawaiipotato

    HSC 2015 MX1 Marathon (archive)

    Re: HSC 2015 3U Marathon y = x + \sqrt{y + \sqrt{x + \sqrt{y + \sqrt{x + ... } } } $ Find $ \frac{dy}{dx} $ in terms of y and x $
  13. kawaiipotato

    HSC 2015 Maths Marathon (archive)

    Re: HSC 2015 2U Marathon ln(x) - 3 / ln(x) = 2 (ln(x))^2 - 2ln(x) - 3 = 0 (lnx - 3)(lnx + 1) = 0 lnx = 3 , lnx = -1 x = e^3 , e^-1
  14. kawaiipotato

    HSC 2015 MX2 Marathon (archive)

    Re: HSC 2015 4U Marathon \int_2^{k+1} \ln(x) dx > $ part b $ $ will give you the answer $ ($ as it is above the y = ln(x-1) curve $) mr mai
  15. kawaiipotato

    100% in 4u maths?

    Isn't that how MC is normally answered?
  16. kawaiipotato

    HSC 2015 MX2 Marathon (archive)

    Re: HSC 2015 4U Marathon No since everyone has a different answer we can deduce that the remaining 9 people must match up to 0,1,..., 8 handshakes each
  17. kawaiipotato

    HSC 2015 MX2 Marathon (archive)

    Re: HSC 2015 4U Marathon Don't think this would fall under any topic in 4U but I found a nice math/logic puzzle $ Five couples go to a party and start shaking hands. You don't shake your spouse's hand or (of course) your own. One of the men, Jake, surveys everyone and asks how many they...
  18. kawaiipotato

    HSC 2012-2015 Chemistry Marathon (archive)

    re: HSC Chemistry Marathon Archive You only have to put the products as water and one other pollutant molecule. I find it easy to just put the products as H2O and CO
  19. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon Is there a case when it's not? o.O
  20. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon Is there a formal proof for that?? If 'c' is a constant independent of x, then you can just bring it out of the integral edit: https://en.wikipedia.org/wiki/Constant_factor_rule_in_integration
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