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Re: I screwed up my half yearlies For of all comiserations on the result, i hate that feeling of knowing you could have done alot better etc. You have not ruined your HSC and have def not ruined your life! How much was it worth? Just work alot harder at physics and try to attain marks that...

namu, stop trying to be the good guy and admit general is shit man lol Bos examiners dont like it, noone likes it. I wouldn't even feel proud with 1st in the state in it, i mean its basically saying ur the least shit maths person out there.

DO NOT do general maths mate, just try and work a bit harder, carefully learn concepts etc. General is shit as and good for nothing, including UAI./

flon, you did fuck all, all of a sudden your willing to help others with your unexplained answers, although the path to answering to Q was obvious, explain your answers.

Re: Fuckin' bikies! LOL!!! That is prob the most obvious thing thats ever been pointed out on BOS.

OP: "thanks addikaye03" Addikaye03: "no worries man", thanks for the rep also" Fair enuf...

to further explain the above: they give u the fact that its arithmetic, a sequence is arithmetic if T3-T2=T2-T1, therefore use that to solve for x. If geometric, T2/T1=T3/T2, same deal

the term is "equidistant", not getting into to you, just to let you know... My advice is: Graph it! u can get so much from a graph on these type of Q and u dont fuck up the focus point for general parabolas of the form (x-h)^2=4a(y-k)

If people have water restictions and there taking effect then the rate at which the water is being used is decreasing, but speed of rate (so to speak) is increasing dy/dx<0, d^2y/2x^2>0, the guy above had it right but his logic on the concavity was wrong.

i suspect u dont have ur calculator is radians mode which is required when dealing with trig functions. [-1/2cos2x](pi/2-->0) [-1/2cos2(pi/2)]-[-1/2cos2(0)] By graphical inspection =1 OR: [-1/2cospi]-[-1/2] (just simplified it) -1/2( cospi-1) so -1/2(-1-1) -1/2(-2)=1 Do u...

sorry bout the delay. Well when an integral is "definite" is has LIMITS. These are the values in which the function's area is determined between. So to find the area between pi/2 and 0, you sub in the larger limit then subtract the smaller limit from that value. A=int(b-->a) x dx ( for...

t=x/Vcosa..(3) y=-1/2.g(x/Vcosa)^2+V(x/cosa)sina y=-1/2.gx.sec^2x+Vxtana y=-1/2.gx(1+tan^2x)+Vx.tana etc etc. eventually get the equation for x,y dependent motion From there u can find an equation for range and max hieght by subbing in x=0 and y=0 in repectively. Eventually...

ex: lost (as in lost-cause) (ex)^2=friend ...see what i did there (ex)^2= ex ex haha

yer i remember him, hes on here quite regularly, he got UAI:99.05 if i remember correctly

derive them, don't remember them

well you need to have done trig functions for a start. HSC 1993 Q3cii) INT (0-->pi/2) sin2x dx [-1/2cos2x](pi/2-->0) [-1/2cospi]-[-1/2] =1

yep, i saw that aswell.

i really felt like a shit bloke writing that haha

that could be right actually

fuck it is too, man my abilty is really depleting these days lol