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Collin

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I don't really know how you want it to be proven.. but I'll just do something trivial:

By definition the square root of a positive real number gives 2 real identical numbers (of opposite magnitudes). I.e there exists 2 real numbers x = a, such that x2 = 2 (and x2 = 2, where x = -a). Now 2 is a positive real number, hence it's square roots are real and they exist.
 

withoutaface

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xiao1985 said:
no no... prove sqrt 2 exist...
as in... u know 1 exist, cuz u can count it...
u know 1/2 exist, cuz u can divide 1 into two , end up in 2 things which if u put together u get 1...

but how do u know sqrt2 exist?! =p
Would this involve using the graph y=x<sup>2</sup> and showing that it's continuous at y=2?
 

xiao1985

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@ jm: too hard... primitive humanity didn't not learn algebra yet
@ collin: how do u know such a nubmer, a s t a^2 exist?!
@waf: again, they dunno algebra...

all they know is elementary geometry, ie area of sq = side x side
 

jm1234567890

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xiao1985 said:
@ jm: too hard... primitive humanity didn't not learn algebra yet
@ collin: how do u know such a nubmer, a s t a^2 exist?!
@waf: again, they dunno algebra...

all they know is elementary geometry, ie area of sq = side x side
i seeee............

I mean, I don't see :confused:

so side of square of diagonal 2 is root(2) ?
 

withoutaface

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That's almost exactly the same as what i proposed, prove that a square of area 2 exists hence prove sqrt(2) exists, except I was using a graphical representation of the areas of squares...
 

xiao1985

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but how do u know a square of 2 unit exist?!
?! can u accurate draw me one waf?!
 

xiao1985

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withoutaface said:
Fuck yes, wait until Monday and I'll do one up for you in solidworks:D
but dear, there are no solid works at the times of pathagoras =p

ok here's a hint 2/4 = 1/2... so if u can draw 4 RIGHT angled triangles, each area 1/2 unit, u are there... =D
 

withoutaface

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xiao1985 said:
but dear, there are no solid works at the times of pathagoras =p

ok here's a hint 2/4 = 1/2... so if u can draw 4 RIGHT angled triangles, each area 1/2 unit, u are there... =D
Xiao if we're talking proving pythagoras I did that a few posts back, minus the boring congruency proofs, which can be done fairly easily. Then just sub in a=1, b=1, and bingo we have c^2=2 hence sqrt(2)=c
 

Frigid

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alicia, could u translate this for me?
Fiona Sit - Si j'etais Carla

Si j'etais elle
je lui dirais de se blottir dans mes bras
tout contre moi

Si j'etais elle
je lui dirais tout ce qu'elle ne lui dit pas
Tout mes reves mes regards et les silences
Mon amour si profond et la douleur de ton absence

Pourquoi tu n'es pas la
Ton sourire a l'aube juste pour moi
Pourquoi ne suis je qu'un nom
Une amie pour toi

Que dois-je faire pour que tu me regardes
Que dois-je te dire pour que tu me parles
Pourquoi ne suis-je qu'un sourire et qu'une ombre
Qu'un ange pour toi oh oh

Une histoire d'amour jamais ne se termine
Tu es mon homme mon heros mon bel Achille
Je n'attendrais plus que tu m'appelles
ma vie serair la plus belle avec toi

Si je pouvais
je fermerais les yeux en pensant a toi
J'imaginerais tous les moments qui passent
Et le courage de ne pas pleurer en ta presence

Elle t'a jete un sort
Tu t'inventes une vie qui n'est pas pour toi
Pourquoi l'aimes-tu encore
Viens vivre avec moi

Partons ensemble le chemin nous est trace
Etre au bout du monde tous deux enlaces
Pourquoi ne suis-je qu'une illusion qu'un mirage
Lointaine image oh oh

Cette histoire d'a our ne sera jamais vaine
Cette passion qui me lie vaut bien la sienne
Je n'attendrais plus que tu m'appelles
ma vie serait la plus belle avec toi
Avec toi...je serais (moi)
 

xiao1985

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Frigid said:
alicia, could u translate this for me?
o_O omg latin?!

@waf: i will post a prove that a sq of 2 unit exist when i come back home... using geometry only... no algebra involved...
 

neo o

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xiao1985 said:
o_O omg latin?!

@waf: i will post a prove that a sq of 2 unit exist when i come back home... using geometry only... no algebra involved...
It's French man :p
 

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