2005 HSC Answers (2 Viewers)

[Paper_Aeroplane]

for question 25 a i) shouldnt z = 624 , as u change it from months to weeks..

or should i have just multiplied it in months? cos if u do it in weeks he cant afford the car..

fuck, may have lost more marks from that mistake.. or am i right :S

that question plagued me to... i sat there for ages trying to figure out which way you were supposed to do it, cuz i knew i had gotten a similar question wrong before by doing it the wrong way, but i couldn't remember which way was right...i just ended up multiplying by 12 tho...

 

[Danni07]

Why would you change it to weeks... because the spread sheet was annual you only had to multiply it by 12

 

[Tommy_69]

With Question 26 a).

wouldn't the answer be 2009 because it says "In December each year, beginning in 2006". Therefore its from

2006 - 2007 - 2008 - 2009 (3 Years)

You must of started from december 2005?

 

[Danni07]

N=2 so it was 2008

 

[Tommy_69]

no if it was 2 it wouldnt be under 120,000 .
it would be at 121,500

therefore n = 3

 

[danieljarvis]

shit.. but it said 52 weeks in a year.. n 52 weeks isnt 12 months.. but then again 1 month isnt 4 weeks. damn

 

[OutOfOrder]

26) a) the machine was bought in 2005, and 2006 is included in the 3 years, so 2006, 2007 and 2008.

 

[Tommy_69]

u are missing the point, read the question

"In december each year, BEGINNING in 2006, the value of the printing machine is DEPRECIATED by 10%.........


meaning the depreciation started in DECEMBER 2006,

 

[SlaminSammy]

the question is saying that in december 2006 it is 10% less. not it starts depreciating by 10% every year since december 2006 thats just absurd

A product begings to depreciate as soon as it is purchased!

In january 2008, the machine is worth $120000

if S = $120000
and Vo = 150000
and r = 10%

the 120000 = 150000 x (.9)^n
so 120000/150000 = (.9)^n
then n = log 0.8 / log 0.9
hence n = 2.11790489 years
0.11790489 = 0.11790489*100 (to get to a percentage of the year)
= 11.79048899 %
11.79048899% = 11.7904889/100 x 12
= 1.414858679 months.

hence approx 2 years and 1.415 months later S = $120000

in dec 2006 - s = $135000

It is a very poorly worded question - probably to cause some people to question their confidence --> hence allowing them to make an obvious mistake. they're really slack ass bastards - damm BOS
in dec 2007 - s = $121500
in jan 2008 - s = $ 120000

therefore the year = 2008

 

[Jayphen]

well I know I got 20/22 for the multiple choice Qs at least. No stupid mistakes - the two I got wrong, I genuinely had no idea about hehe. woo!

 

[Drop20]

answer to 28.b. (iv) is$23

Aww hell no, i got $15.50 for the very last question. I think i divided 3100 (read from the graph) and divided that by 200. Whst did everyone else do to get $23?

 

[Casmira]

I reckon it was really poorly worded as well, I mean during 2006? if you think about it, the effect of 15% interest being taken off only really happends at the end of the year not "during" (unless it happend monthly"

i just put 2008 anyway

 

[danieljarvis]

well, according to these marks i got about 99 raw mark .. i got 25 a) i .. the Z part wrong.. but in ii) i did it correct with my working.. so i should get full marks shouldnt i.?!

and drop 20.

selling 200 tickets means C = 700 + 12 x 200

C = 3100

to make a profit of 1500

C + 1500 = 4600

4600 / 200 = $23

 

[green_beans]

can someone pleeeeease scan the questions and multiple choice booklet?!??!

 

[Muzzaw]

94 or 95, sweet.

 

[Muzzaw]

Aww hell no, i got $15.50 for the very last question. I think i divided 3100 (read from the graph) and divided that by 200. Whst did everyone else do to get $23?

Find the cost to host 200 people, which I think was $3100.

Find the ticket price to break even at $3100. 3100/200 = $15.5 I think.

Find the ticket price to make $1500. 1500/200 = $7.5.

Add the two together, $23.

 

[Jayphen]

Woo, I just worked out my marks and I got around 91-92% Stoked.

 

[Casmira]

i dont want to think i got 91 because ill probably get like 80 back lmao

 

[Jayphen]

Wasn't the question asking you to find out the formula for finding the cost of each ticket?

So C = 12x + 700 / how ever many people (can't remember)

??

nah, it was
"Write a formula for the cost ($C) of running the dance for x people"

 

[Picle]

i did $C=300+400+(12x) still should get the same marks just didnt add the others