2006 HSC Mathematics Solutions (1 Viewer)

[T.Goodhew]

Here are my worked solutions to the Mathematics (2Unit) HSC 2006. I apologise to those who downloaded the earlier versions, there were some minor calculation errors that have been fixed in the newer version of the solutions available here.

Fixes:

• The proof of Q6 a) iii. is now included as is Q7 which were accidentally left out.
• Small trig evaluation errors made in evaluating sin of 2pi/3 were corrected.
• The final two questions Q10 b) iv. and v. will be added shortly.

Once again I sincerely apologise if you were worried because you downloaded a earlier solution file. You must excuse me I was working the solutions late between 11-12pm at night and small errors seem to be the consequence of that.

Mathematics (2Unit) HSC Solutions - 2006 (v1.25)
(Question 10 b) iv. v. will be included in v1.3)

 

[fishy89sg]

oh these are so hot

 

[2006hsc]

just a few mistakes but..but u did well. But you missed a whole question! 7 i think..

 

[T.Goodhew]

Oh , I did too... i have written the solutions to Q7... they will be included in this file and available to download by 12:30pm Today.

if you could forward the mistakes you found to my email that would be apprecitated!!

 

[mlinger]

Question 4a ii and iii are wrong.. use cosine rule instead... answer for bd should have been the square root of 27

 

[Bijs]

Isn't the sine rule question in q1 wrong too?

 

[Keskimo]

gah how could you be bothered doing the whole paper for the second time? i never want to see maths again - except your solutions to see how i went! oh, and chemistry mole/equation work...

 

[Keskimo]

don't worry - thought you were a current hsc student

 

[da1]

why doesn't it let me look at the solutions stupid comp

 

[sando]

yeh its not working for me either.. wats the deal ?

 

[lissamaher]

Question 3: c) (ii) you have 13/2, shouldnt it be 14/2?? as n=14?? or am i wrong

 

[coolzor]

man this is the fastest dlz eva....

 

[shinji]

i have a lil discrepancy with 2)c)
i got a far more complicated equation than that.
i got the same gradient.

but instead of doing x=0 and y=1,
i used found out y via x-> y=cos2x
which gave y= 1/2

and then did y-y1=m(x-x1)
which equaled
y- 1/2 = -(sqrt3)[x- pi/6]
2y - 1 = -x[sqrt3] + [[pi](sqrt3)]/6
-> x[sqrt3] + 2y - 1 - (pi[sqrt3])/6 = 0



welll that's just me .. . lol

 

[sando]

in 2 (c) ... shouldnt the y-value be ...... y = cos2 (pi/6) = 1/2

im no maths expert.. but correct me if im wrong

 

[sando]

yes.. i got same at Shinji.. and he is like boy genius lol

 

[T.Goodhew]

i have a lil discrepancy with 2)c)
i got a far more complicated equation than that.
i got the same gradient.

but instead of doing x=0 and y=1,
i used found out y via x-> y=cos2x
which gave y= 1/2

and then did y-y1=m(x-x1)
which equaled
y- 1/2 = -(sqrt3)[x- pi/6]
2y - 1 = -x[sqrt3] + [[pi](sqrt3)]/6
-> x[sqrt3] + 2y - 1 - (pi[sqrt3])/6 = 0



welll that's just me .. . lol

y - 1/2 = -(sqrt3)[x - pi/6]
2y -1 = -2(sqrt3)[x - pi/6]
2y -1 = -2(sqrt3)x +([sqrt3]pi/3)
2(sqrt3)x +2y -1 -(pi[sqrt3]/3) = 0

i think you will find ... Changed the solutions accordingly grr.. stupid mistakes i made late at night.

 

[shinji]

woops. mybad. lol
a little misclculation error for me as well there. haha
im pretty sure ididn't do it in the exam~ XD

and ur welcome =D

@sando: me? lil genius boy? i wish! haha

 

[falbrav]

I've been trying to open these solutions all day but it just wont seem to work and i was wondering whether any1 had any suggestions?

 

[rolfey24]

I've been trying to open these solutions all day but it just wont seem to work and i was wondering whether any1 had any suggestions?

yeh i had probs as well. insted of opening jsut save it to ur pc. worked 4 me.

 

[T.Goodhew]

yeh i had probs as well. insted of opening jsut save it to ur pc. worked 4 me.

I've moved the file to a faster server, so you should be able to download the solutions easier now, thanks shinji for your help