Correct me if I'm wrong, but here's what I get:

Yeah 8 is B which is just by subbing in (-x) into the equation.

Then 9 is C. So dy/dt = dy/dt * dt/dx = -x/y * 1/y = -x. Then, consider that in the first quadrant, y is positive so dx/dt is positive, and hence x is increasing. So it seems like it goes clockwise. You can do this for other quadrants, e.g. in the third quadrant y is negative so x is decreasing, again going clockwise.

Then 10 is B, as it is a concave up function by the definition. So draw a line from (0,f(0)) to (1,f(1)) and see that the graph will always lie under this, and hence the intergral will be less than the midpoint if that makes sense. A counter example to A is x^2, a counter example to C is x(x-2), and a counter example to D is x(2-x).