HoldingOn
Active Member
What would 57 align to? Would it be enough for E4?
Easily a E4, probabbly to 94 or 95What would 57 align to? Would it be enough for E4?
idk what it aligns to but it would definitely be e4What would 57 align to? Would it be enough for E4?
How do you know?Easily a E4, probabbly to 94 or 95
Take a look at this link: http://rawmarks.info/wiki/Mathematics_Extension_1How do you know?
For c iii), I reckon you had to prove x, x1 and x2 before finding the ratio, like how do you know it's a gp otherwise ~ Not sure tholooking at 68 or 69 out of 70. is it possible for a 69/70 to align to a 100?
for 14c)iii) did we have to prove that |r| < 1 or are we allowed to assume this since we are given in the wording of the question that a limiting sum exists? all i did was find x and x1 (using similar triangles), said r = x1/x and then substitued into a/(1-r)
and for 14b)ii) did we have to write the actual number or could we just leave it as 23C4 * 2^(19)
you know its a GP because the question said that a limiting sum exists, and limiting sums only exists for GPs with |r|<1For c iii), I reckon you had to prove x, x1 and x2 before finding the ratio, like how do you know it's a gp otherwise ~ Not sure tho
for b ii), maayyybe (I did) but surely the marks is for understanding selector A and B's role, and then using part i, not calculator shit
I would be quite surprised if you had to write out the actual number for 14 b) ii).looking at 68 or 69 out of 70. is it possible for a 69/70 to align to a 100?
for 14c)iii) did we have to prove that |r| < 1 or are we allowed to assume this since we are given in the wording of the question that a limiting sum exists? all i did was find x and x1 (using similar triangles), said r = x1/x and then substitued into a/(1-r)
and for 14b)ii) did we have to write the actual number or could we just leave it as 23C4 * 2^(19)
yeah I think it was like 4 billion something idk, i just saw 2^(19) and automatically thought it would be too big so i left the answer as 29C4 * 2^(19)I would be quite surprised if you had to write out the actual number for 14 b) ii).
oh shit i think i forgot to change it to radian mode as well, but i don't recall having to put down anything for theta i just replaced the whole trig function with something. oh well whatever i probably screwed that up anywayughhh I forgot to change my calculator to RAD mode for the ferris wheel question, and also didn't see that the domain of the function was x>1!! Sighhh silly mistakes
I haven't seen the question wording, but did it say it's a GP? Non-GP sums can also have limiting sums.you know its a GP because the question said that a limiting sum exists, and limiting sums only exists for GPs with |r|<1
so it can be assumed that x, x1, x2, ... form a GP with |r|<1 otherwise a limiting sum wouldnt exist
the question said something like 'show that the limiting sum of the areas of the quadrants is X' so you already know that the sum converges to X and as far as 3u maths goes only geometric sums convergeI haven't seen the question wording, but did it say it's a GP? Non-GP sums can also have limiting sums.
Without having seen the question, I think that if you know (either via proof or by being given it) that it's a GP, and the question tells you the sum converges, then you shouldn't need to waste time proving |r| < 1.
na u got that right, cause thats the exact same thing i did, but the answer should be 19. somethingoh shit i think i forgot to change it to radian mode as well, but i don't recall having to put down anything for theta i just replaced the whole trig function with something. oh well whatever i probably screwed that up anyway
oo yay i got 19. something as well! hopefully the only marks i lose in this exam are from the questions I couldnt dona u got that right, cause thats the exact same thing i did, but the answer should be 19. something