# Answers to General Maths Exam (1 Viewer)

#### PC

##### Member
For those interested ...

Double checked a few of them. Let me know of any errors.

In any case, it's done now. Move on to the next exam or if you've finished, have a drink for me!

SECTION I
1. B
2. A
3. D
4. A
5. C
6. A
7. D
8. C
9. A
10. B
11. B
12. C
13. C
14. B
15. A
16. D
17. C
18. C
19. A
20. D
21. D
22. B

SECTION II
QUESTION 23
(a) (i) \$5000
(ii) Rose's investment, by \$2000
(iii) 1 year
(b) (i) 144 m3
(ii) 12 hours
(iii) 8000 litres
(c) (i) 45 crocodiles
(ii) 60 crocodiles

QUESTION 24
(a) (i) 11.4
(ii) Removing the outlier will decrease the mean but the median will stay the same.
(b) 3.6 sec
(c) (i) €480
(ii) The Australian dollar will now buy more Euros. The gradient of the line will increase.
(d) (i) The females that attend tend to be older than the males.
(ii) 64
(iii) 172.5
(iv) In the grouped frequency distribution table, the class centres are used as the ages and not the actual ages. From the stem-and-leaf plot, the actual ages are used.

QUESTION 25
(a) If two coins are tossed, the probability of obtaining at least one head is 3/4.
(b) 58 degrees
(c) (i) 1/5
(ii) diagram, probabilities are 5/10, 3/10, 2/10, then 4/9, 3/9, 2/9, 5/9, 2/9, 2/9, 5/9, 3/9, 1/9
(iii) 14/45
(d) (i) Test 2 mark is better as it is further from the mean. z-score for Test 1 is 0.48 and for Test 2 is 0.67.
(ii) 126 students

QUESTION 26
(a) (i) 5 km/h
(ii) 18 km
(iii) 236 degrees
(b) (i) 9.1%
(ii) \$41145
(iii) \$8443.50
(c) Total value = 100(1.06)21 + 100[ (1.06)21 – 1 / 0.06] = \$4339.23
Interest = 4339.23 – 22 x 100 = \$2139.23

QUESTION 27
(a) (i) Length 12 m, Width 6 m
(ii) A = l(l – 6)
(iii) If length is 6 then width is 0 which is not possible. If length is less than 6 then width is negative which is also not possible.
(iv) Length 15 m, width 9 m
(v) graph - two bits, horizontal line up to A = 150 then diagonal line.
(vi) Company B
(b) (i) C = 24 + 7300d
(ii) d = 0.031
(iii) Cost is \$476.60 so does not double
(iv) 4660 hours

QUESTION 28
(a) (i) 5/18
(ii) +\$0.75
(iii) Loss of 25 cents per game
(b) 22.784 cm2
(c) (i) 50.4 cm2
(ii) 3500 cm2

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#### LatK7

##### Member
Judging from that i got about 80%

#### ronan01

##### New Member
has anyone got the exam? they wouldnt let us take them...

#### Paintbrush

##### Member
Going from those 90%?

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#### Paintbrush

##### Member
ronan01 said:
has anyone got the exam? they wouldnt let us take them...
Yeah, we were allowed to take ours home.

#### RaisedByWolves

##### Member
24 d) ii) three males are aged 22, but 2 males and 2 females are aged 64 so the mode is 64

#### ronan01

##### New Member
is someone allowed to post it up (or send me it).. i forget half the multi choice questions and stuff lol

#### PC

##### Member
Absolutely correct. Cheers.

#### Snowfreq

##### :)
RaisedByWolves said:
24 d) ii) three males are aged 22, but 2 males and 2 females are aged 64 so the mode is 64
SHIT. I didn't see that. Arghhhhh!

#### champo14

##### Member
RaisedByWolves said:
24 d) ii) three males are aged 22, but 2 males and 2 females are aged 64 so the mode is 64

I did the mean. WHY!

#### AlexW23

##### New Member
25. d) ii) I PUT A PERCENTAGE, so hopefully i get 1/2 marks.

#### Tom2nv

##### Member
Hey question 3 of multiple choice i think as 280 x 4 =1120 x 0.175 = 196 as its 17.5 % of the pay she wuld receive had she been workin thus its A in my opinion

#### AlexW23

##### New Member
I had Total = (280 x 4) x 1.175 (117.5%)
= 1316\$

#### champo14

##### Member
Question 28b) I had area as 22.78cm2. What am I doing wrong?

Side length is 2.828, right?

#### pattii

##### condom endorser
QUESTION 27: A) A RECTANGULAR PLAYING SURFACE IS TO BE CONSTSRUCTED SO THAT THE LENGTH IS 6 METRES MORE THAT THE WIDTH

.... did u read the q? the graph was on the length and area not on the lenght and width....

#### Tom2nv

##### Member
But doesnt \$1316 sound strange as he is not working yet he is receiving more money in the 4 weeks than if he had been working the 4 weeks

#### Snowfreq

##### :)
champo14 said:
Question 28b) I had area as 22.78cm2. What am I doing wrong?

Side length is 2.828, right?
Hmm... wtf. I got 22.784.

To find the side:
H^2 = 2^2 + 2^2 = 8
H = SQRT(8)

A = 2.598 * (SQRT(8))^2 + (0.5 * 2 * 2) = 22.784

Did I do something wrong?

PC, how'd you get 32.784cm^2?

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#### pattii

##### condom endorser
champo14 said:
Question 28b) I had area as 22.78cm2. What am I doing wrong?

Side length is 2.828, right?
i found the side by using pythagoras..

so c^2=2^2=2^2
c^2=8
so i squarerooted the 8 n got
22.828

then used the formula given

so 2.598x22.828^2
=20.784

then 1/2xbxh
1/2x2x2
=2

so 2+20.784
=22.784

#### pattii

##### condom endorser
Snowfreq said:
Hmm... wtf. I got 20.784.

To find the side:
H^2 = 2^2 + 2^2 = 8
H = SQRT(8)

A = 2.598 * (SQRT(8))^2 = 20.784

Did I do something wrong?
dude you forgot the triangle

#### blake13

##### New Member
Hi

Was just wondering if it would be possible for someone who was able to take the general maths 2007 hsc exam home, to post it. We weren't able to take our copy home. Thanks