Auxillary method question (1 Viewer)

5uckerberg

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For part a what can we turn into?
Next question we have
we can turn that into . This becomes
part b is just using these two values and the second one is just the auxillary angle method. A useful technique there would be to draw out a right angled triangle with R being the hypotenuse and then finding the angle between the little sides and then you are done because the last step is simple simplifying.
 

Lith_30

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for a.






and ye should be pre straight forward from there

b.
solve tanx = -1 and cosx - sinx = 1

ps. sorry for latex cbf
For part a what can we turn into?
Next question we have
we can turn that into . This becomes
part b is just using these two values and the second one is just the auxillary angle method. A useful technique there would be to draw out a right angled triangle with R being the hypotenuse and then finding the angle between the little sides and then you are done because the last step is simple simplifying.
Thanks guys, I get it now
 

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