x0*x4 and x1*x3 are the two cominations of x4 in respective order to the brackets...fullonoob said:find the coefficient
(3+x)(1-x)^15 find the term in x^4
(2-5x+x^2)(1+x)^11 find the term in x^9
:jaw: help please + full working out
you are right.bored of sc said:x0*x4 and x1*x3 are the two cominations of x4 in respective order to the brackets...
1C0*3*x0*15C4*(1)11(-x)4 + 1C1*30*x*15C3*112*(-x)3
= 4095x4 -455x4
= 3640x4
= 3640
I did this quick, it might be wrong.
i never use pascals triangle, i just use the calculatorclintmyster said:just a quick question, you know for the binomials with n>6 or something do you guys tend to use combinations over pascals triangle?
um, no.clintmyster said:just a quick question, you know for the binomials with n>6 or something do you guys tend to use combinations over pascals triangle?