Chemistry Predictions/Thoughts (1 Viewer)

[carrotsss]

Just because you found it easier doesn't reflect the rest of the student population. One student in the hall just gave up and left. Admittely he probably a bit simple, however quantitivae calculations only benefit MX2 nerds. there are also students who get marks from wordy question

that’s fair ig, from talking to friends most found it easier but a lot of us are better with quantitative stuff so it might not be super representative of everyone

 

[Life'sHard]

Just because you found it easier doesn't reflect the rest of the student population.

Skill diff

 

[jc7726]

that test was so much nicer than i expected. i was thinking i was gonna get screwed over and maybe a raw 70 but if everything goes right i might get 90+

 

[year10studentpreparin]

that’s fair ig, from talking to friends most found it easier but a lot of us are better with quantitative stuff so it might not be super representative of everyone

I think its more that my mx2 mates study a lot more because thats expected of them and why they can do mx2 because of studying a lot rather than an advanced mate of mine who just plays video games all days and gets crap plus he fails advanced too

 

[Aminza21]

what we getting for q 19 and 20 mc

 

[carrotsss]

what we getting for q 19 and 20 mc

if im remembering the questions correctly, B and D

 

[qldbulls]

No one by any chance got a tertiary alcohol for Q36?… . Spectroscopy question.

Tertiary can't oxidise into C

 

[Xyzpt]

Tertiary can't oxidise into C
[/QUOT


I just left it as a tertiary alcohol for C

 

[dumNerd]

Can somebody send the paper

 

[sid_05]

seems like a lot of us finished today on chem lol,
feels like nobody here does physics???

I do!!!!

 

[Adrian_jnader]

Did anyone upload solutions??

 

[tywebb]

Can somebody send the paper

See post #253 for paper

 

[lounjg]

0.1?

how? I was trying to solve for 2 terms, (x being the change in equilibrium, y being the how much co2 was added). They said they were equal so keq = 1/x, I got this equation in the end. didnt want to waste my last 20 mins trying to solve so i cut my losses. I still cant solve it lol.

 

[jc7726]

i don't know if they're talking abt something completely different, but you might have been able to use concentrations to find how much was added instead. since [CO2] = [CO] let [CO2] = x
x/x^2 = 10
x = 10x^2
1=10x
x = 0.1 for the conc of both

 

[jc7726]

how? I was trying to solve for 2 terms, (x being the change in equilibrium, y being the how much co2 was added). They said they were equal so keq = 1/x, I got this equation in the end.View attachment 41177 didnt want to waste my last 20 mins trying to solve so i cut my losses. I still cant solve it lol.

sorry meant to reply, ^

 

[lounjg]

i don't know if they're talking abt something completely different, but you might have been able to use concentrations to find how much was added instead. since [CO2] = [CO] let [CO2] = x
x/x^2 = 10
x = 10x^2
1=10x
x = 0.1 for the conc of both

Yeah this is correct
lol i think of these long ass equations but not smth simple. Also for q31 i done an absoprbance of 0.56 insted of 0.66 RIPP. I also squared the wrong number when finding keq max 4 marks theyre giving me

 

[Retrodawn]

but didnt you have to find the amount of co2 added or something

 

[dumNerd]

Why was there no non basic theory what so ever in this exam bruh.

I mean I think chem should be this way but unfortunate for people who don’t have calculations as their strong suits

 

[=)(=]

i don't know if they're talking abt something completely different, but you might have been able to use concentrations to find how much was added instead. since [CO2] = [CO] let [CO2] = x
x/x^2 = 10
x = 10x^2
1=10x
x = 0.1 for the conc of both

pretty sure i got 0.169 added

 

[=)(=]

Why was there no non basic theory what so ever in this exam bruh.

wasnt last yr the same tho and every year prior