complex number help (1 Viewer)

[noobking]

see attachment

 

[jyu]

see attachment

:wave:

 

[haque]

For these type of questions u can also just take the modulus of both sides, so lets denote the modulus symbol with "[" these brackets
then z= 2+it/2-it
take modulus of both sides
[z]=[2+it/2-it]
=[2+it]/[2-it]
=sqrt(4 +t^2)/sqrt(4+t^2)
=1 i.e modulus of z is 1 and so the same answer as jyu said.

 

[jyu]

For these type of questions u can also just take the modulus of both sides, so lets denote the modulus symbol with "[" these brackets
then z= 2+it/2-it
take modulus of both sides
[z]=[2+it/2-it]
=[2+it]/[2-it]
=sqrt(4 +t^2)/sqrt(4+t^2)
=1 i.e modulus of z is 1 and so the same answer as jyu said.

Just wondering what type of questions that you were referring to.

:wave:

 

[haque]

Well locus q in the form of z=c+it/c-it where c is a constant-often giving the modulus etc isn't enough because z traces out the circle either clockwise or anticlockwise, found by subbing in values-that would probably give a more complete locus-sorry bout that i should stated clearly rather than say "type"