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complex number help (1 Viewer)

haque

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For these type of questions u can also just take the modulus of both sides, so lets denote the modulus symbol with "[" these brackets
then z= 2+it/2-it
take modulus of both sides
[z]=[2+it/2-it]
=[2+it]/[2-it]
=sqrt(4 +t^2)/sqrt(4+t^2)
=1 i.e modulus of z is 1 and so the same answer as jyu said.
 

jyu

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haque said:
For these type of questions u can also just take the modulus of both sides, so lets denote the modulus symbol with "[" these brackets
then z= 2+it/2-it
take modulus of both sides
[z]=[2+it/2-it]
=[2+it]/[2-it]
=sqrt(4 +t^2)/sqrt(4+t^2)
=1 i.e modulus of z is 1 and so the same answer as jyu said.
Just wondering what type of questions that you were referring to.

:) :) :wave:
 

haque

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Well locus q in the form of z=c+it/c-it where c is a constant-often giving the modulus etc isn't enough because z traces out the circle either clockwise or anticlockwise, found by subbing in values-that would probably give a more complete locus-sorry bout that i should stated clearly rather than say "type"
 

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