CSSA Trials: 3U Maths thoughts (1 Viewer)

[TrentsUnicorn]

i found it an overall pretty good exam, could one of u guys let us know how u went on that question with the rate of change with the weather balloon

With the rate of change of the angle? Lol I did it, don't know how right it was though.... Got some fraction, don't remember exactly though :/ think I got 1/40? But don't remember

 

[dunjaaa]

What was the question?

 

[enigma_1]

well done son.

lol stop talking to yourself

 

[Vabz]

What did u get for the range (R).

 

[enigma_1]

What did u get for the range (R).

What question was this??

 

[Vabz]

The last part to the projectile motion

 

[atlas10]

40.5

 

[km1307]

What did your graph for the inverse trig question look like?

 

[Thank_You]

Fuck me sideways, skipped easy shit like:

cos(theta) = 1/5. Find tan(theta/2).

Now I know how to do it.

Couldn't see the circle geometry question, wasted 15mins on it.

Now I know how to do it.

Couldn't see the pattern in the mathematical induction question.

Now I know how to do it.

Got the equation wrong for the graph, which the answer was actually: 1/2[(x-2)^2(x+1)]

That last projectile question was fairly easy, but when solving via sum and product of roots, accidentally left out an 'R'. Fuckkkkkk,

There goes at least 7-10 marks

40.5

Yeah, that answer is right

What did your graph for the inverse trig question look like?

You just draw the left side the graph and reflect it about y=x

was actually probably easier than past CSSA papers by quite a significant amount.

Agreed, yet still I screwed up

With the rate of change of the angle? Lol I did it, don't know how right it was though.... Got some fraction, don't remember exactly though :/ think I got 1/40? But don't remember

Yeah I got that!!

 

[photastic]

How do you know the answer for the polynomial already?

 

[enigma_1]

oh god this is making me depressed

 

[faisalabdul16]

How did you guys do

cos(theta) = 1/5. Find tan(theta/2).

I did it by finding sin(theta) and cos(theta) in terms of (theta/2) and then getting tan(theta/2) which only took me 4 lines, but i have this feeling there's a quicker way...

Did anyone do it a faster way?

 

[photastic]

How did you guys do

cos(theta) = 1/5. Find tan(theta/2).

I did it by finding sin(theta) and cos(theta) in terms of (theta/2) and then getting tan(theta/2) which only took me 4 lines, but i have this feeling there's a quicker way...

Did anyone do it a faster way?

Lol, I did the longest method by finding tan(theta) then use the double angle of tan lolol

 

[dunjaaa]

Let t=tan(x/2), (1-t^2)/(1+t^2) =1/5, cross multiply, it comes out in 1 line.

 

[faisalabdul16]

Lol, I did the longest method by finding tan(theta) then use the double angle of tan lolol

This is how i did it step by step for anyone who didnt understand what i said...

 

[faisalabdul16]

Let t=tan(x/2), (1-t^2)/(1+t^2) =1/5, cross multiply, it comes out in 1 line.

ahhhh genius! how stupid of me lol, idk how i didnt think of that lol

 

[photastic]

ahhhh genius! how stupid of me lol, idk how i didnt think of that lol

Now i feel stupid.

 

[faisalabdul16]

Now i feel stupid.

haha dw as long as you got the answer

 

[photastic]

haha dw as long as you got the answer

Yea but, it's all about time efficiency, learnt my lesson for the actual thing

 

[dunjaaa]

Also, is 0 < theta < 90? or 270 < theta < 360? Depending on which of these conditions are specified will determine whether tan(theta/2) is positive or negative.