betraya
ABC
I did it by y= integral of xlnx-x and replacing by x-2 for 10a). Took 2 + pages for proving 10b i and ii
Since we don't know how to integrate a log, you needed to basically turn the whole thing on it's side and integrate under the curve bounded by the y-axis.dolbinau said:10b got it all but for a, was it a trick? How did we do it?
To find the area of the upper triangle, what you could have done was use the similar triangles ratio formula to obtain an expression for line MP, then add the areasgaaay said:10 a was easy
10 b got me good
i couldnt find the area of the upper triangle :S
i got that.dolbinau said:My minimum value of x was l/root 2 iirc
The length was a like root something minus soomething times x
hahaha holy shit i think i did that too.dolbinau said:Damn for 10a I just said the unshaded area was the answer how many marks would I get?
yessmozdaddy said:OK so im not sure if it was correct but i think my final answer for 10a was:
5ln5 - 4.
This sound right?
???pyjamapants said:Btw, what justifcation did you use for x being l/rt2 ???
I had something pathetic like the ratio of x to l had to be greater than one otherwise the gate wouldn't intersect. But I know it's wrong.