Halp!
Mudkip94 Member Joined Aug 1, 2009 Messages 289 Location Your Mom Gender Male HSC 2011 Dec 16, 2009 #1 Halp!
Trebla Administrator Administrator Joined Feb 16, 2005 Messages 8,391 Gender Male HSC 2006 Dec 16, 2009 #2 tan 45° = 2tan (22.5°) / (1 - tan²22.5°) 1 = 2tan (22.5°) / (1 - tan²22.5°) then solve the quadratic equation for tan 22.5°
tan 45° = 2tan (22.5°) / (1 - tan²22.5°) 1 = 2tan (22.5°) / (1 - tan²22.5°) then solve the quadratic equation for tan 22.5°
adomad HSC!! Joined Oct 10, 2008 Messages 543 Gender Male HSC 2010 Dec 16, 2009 #4 Trebla said: tan 45° = 2tan (22.5°) / (1 - tan²22.5°) 1 = 2tan (22.5°) / (1 - tan²22.5°) then solve the quadratic equation for tan 22.5° Click to expand... also, letting u= tan 22.5 makes it look neater. and remember that tan 22.5 is positive so u have to reject the negative answer
Trebla said: tan 45° = 2tan (22.5°) / (1 - tan²22.5°) 1 = 2tan (22.5°) / (1 - tan²22.5°) then solve the quadratic equation for tan 22.5° Click to expand... also, letting u= tan 22.5 makes it look neater. and remember that tan 22.5 is positive so u have to reject the negative answer
M Macdaddy. Banned Joined Oct 5, 2009 Messages 19 Gender Male HSC 2008 Dec 16, 2009 #5 Whatever is a surd?
Mudkip94 Member Joined Aug 1, 2009 Messages 289 Location Your Mom Gender Male HSC 2011 Dec 16, 2009 #6 Thanks guys!