withoutaface
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We don't get it back for ages.jesshika said:aww!! can someone post up the cssa 04
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We don't get it back for ages.jesshika said:aww!! can someone post up the cssa 04
withoutaface said:Throw some numbers at me and I'll be able to tell you if thats what I got.
nah you sub in from the S(k) thing that 5<sup>k</sup>>4<sup>k</sup>+3<sup>k</sup>za said:for the induction question
c how u get:
5.5^k > 4.4^k + 3.3^k
can u divide it all by 5. ending with:
5^K > (0.8)4^k + (0.6)3^k
then u can say, seeing as though 5^k > 4^k + 3^k, then it is obviuosly greater than (0.8)4^k + (0.6)3^k.
???????????????????
I dont have them, nor can I remember what they specifically were, sorry.Sirius Black said:Hi, Withoutaface, would u plz post up the Q7 the two projectile one here? i am quite interested in it![]()
that's not what i got >_<za said:yeah it was 2(pi^2)/3
yay!..........acmilan1987 said:From that rate of change of surface area if i remember correctly i got -5 cm/s. Did anyone else get that
i got 3pi<sup>2</sup>/2...lolza said:yeah it was 2(pi^2)/3
damn it!withoutaface said::.dx/dt=v
dt/dx=1/v
then integrate, find the constant, and simplify.