Factorisation (1 Viewer)

Blitz_N7

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Is there a way to factorise:
m^3 -3m^2 +2m +3m^2n-3mn+3mn^2-3mn+n^3-3n^2+2n into:
(m+n)(m+n-1)(m+n-2)? Thx in advance.
 
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braintic

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Is there a way to factorise:
m^3 -3m^2 +2m +3m^2n-3mn+3mn^2-3mn+n^3-3n^2+2n into:
(m-n)(m-n-1)(m-n-2)? Thx in advance.
I am going to guess that your first line is an intermediate stage in your working for a different question.
If so, could you post the actual question - there might be an easier way to do it.
 

Ekman

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Is there a way to factorise:
m^3 -3m^2 +2m +3m^2n-3mn+3mn^2-3mn+n^3-3n^2+2n into:
(m-n)(m-n-1)(m-n-2)? Thx in advance.
I got (m+n)(m+n-1)(m+n-2), is there something wrong with the question or am I simply wrong?

Edit: After doing some expansion, I realised that multiplying -n three times will not give positive n^3, so there must be something wrong with the answer
 
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Blitz_N7

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The actual question is proving: (m+n)C3=mC3+mC2nC1+mC1nC2+nC3. Combinations :/
 

rand_althor

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It is easier if you consider the coefficient of in and . You know that the coefficients of in each of these expansions will be equal as .
 
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Ekman

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If you still want to know how to do it algebraically:



 

YouCantMakeMe

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Probably just write it similarly to that (though you probably wouldn't need full sentences), and maybe draw a diagram if it helps, like:



where each * represents a distinct object.
And nice LaTex skills haha.
 

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