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Find log (1 Viewer)

addikaye03

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You've skipped a few steps here that are going to confuse some people.

What I was pointing out was that your method is limited to simple indice-balancing questions. This works but denies students a deeper understanding of what logarithms are all about.

A simple:

7x = 36
log 7x = log 36 [taking logs]
x log 7 = log 36 [Using log laws]
x = log 36 / log 7

is the cleaner and more powerful method rather than muddying the water with equivalence of indices. As I was saying, leave that to the monkeys.

Best Regards
Herremann
dude... i obviously knew that i skipped a few steps, i was just trying to outsmart your Q, dw...
 

zazzy1234

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Monkey: thats easy you noob,

log7 36=x

7^x=36

7^x=7^(ln36/ln7)

therefore x=ln36/ln7 or/ 1.841564442

Me: the monkey's pretty amazing

Monkey: Got anymore wise guy?

Me: Aww now your getting rude
(log36)
--------
(log7)

it should give 1.84 (2dp)
 

bored of sc

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log48
= (log 8) / (log 4)
= (log 23) / (log 22)
= [3 (log 2)] / [2 (log 2)]
= 3/2
 

zazzy1234

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umm...yer? what's your point? Put 7^1.841564442 into your calculator and tell me what you get
first of all

(log36)
---------
(log7)

is the way u would type it ur calculator lol

and how do u teach ur self ext 2 math, r u sitting a HSC for it
 

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