Further probability question - HELP! (1 Viewer)

[monopoly19]

Q. Each time a competitor shoots at a target he has a 0.2 probablity of hitting the target. He has five shots at the target. Find the probability that:

i. he hits the target on the first three shits and misses out on the other two

ii. he hits the target on 3 out of the 5 shots

I know how to do part ii, but I can't get part i. The answers are below.






A. i. 0.00512 (how???)
ii. 5C2 * (0.8)^3 * (0.2)^2 = 0.0512

 

[Newbie]

1/5 * 1/5 * 1/5 * 4/5 * 4/5 = 16/3125 = 0.00512

 

[monopoly19]

Well, don't I feel like a f*ucking retard. Thanks newbie.

 

[bMaN oNe]

Originally posted by monopoly19

ii. 5C2 * (0.8)^3 * (0.2)^2 = 0.0512

I think ure mixed up here :S Sorry if i'm mistaken, but isn't it:
5C3 * (0.2)^3 * (0.8)^2 = 0.0512
I think it is, answers right just the working