it was x = 9^(1/3)davOmeter said:Omfg, that exam was /wrist worthy
Did anyone get the newtons method question?
Like wtf,there was no function?!
Really? are 50s-60s the kind of raw marks that get bands 5 and 6? I mean, I would love for that to be true, butI thought it was more like 70s?brendanstacey said:DONT DROP IT!!!
If your getting 50-60 for that exam your basically garanteed a band 6. Remember to compare yourself to the rest of the state, of whom most would fail this badly.
i would also like to know this...anyone care to make an educated guess at the minimum raw mark for that test that would probably gain a band six?lorikeet said:Really? are 50s-60s the kind of raw marks that get bands 5 and 6? I mean, I would love for that to be true, butI thought it was more like 70s?
That question confused me a bit too but in the end I got it. just minus the 3root9 to the other side so it becomes x - 3root9.davOmeter said:Omfg, that exam was /wrist worthy
Did anyone get the newtons method question?
Like wtf,there was no function?!
That's what I initially started to do, then realised my logical flawproringz said:That question confused me a bit too but in the end I got it. just minus the 3root9 to the other side so it becomes x - 3root9.
Oh yeah, I understand your point. I subbed my answer in and it was right, but probably not full marks. But then again if x= 3root9 and if your're finding x, then x-3root9 should = 0.DunnyBasher said:That's what I initially started to do, then realised my logical flaw
You are trying to obtain a value for x=3rt9, so...you cant use 3rt9 in obtaining that answer, otherwise it completely defeats the purpose of using Newton's method.
So, I just cubed and subtracted the 9.
You would have got the correct answer, but whether you will get full marks is questionable.
vds700 said:it was x = 9^(1/3)
x^3 = 9
f(x) = x^3 - 9 = 0
Yeah I got this.davidlee90 said:no one's talking about the crazy 3D trig yet... you guys found them easy???
i had 10 degrees and 40 mins as my answer. Anyone else?
Well if you were that example, y^2 = x,ashraf91 said:but y would u do dat, introdcing more solutions wen 9^[1/3] is a constant, it like y^2=x isnt d same as y=x^0.5, please correct me cause i fink im rong
I wasn't put off by the diagram; I was put off by the bearings.Zephyrio said:Yeah I got this.
It wasn't that hard, was it? I think some people were just put off by the diagram. All you had to do was use the sine rule in the bottom triangle, and use tan in the left-side triangle.
I'm not sure, but i was always taught that with a question where they give u a dN/dt and u have to show that N satisfies it, then u have to integrate the dN/dt because they asked u to show, and that differentiating the N would only be a verification.erm said:weren't you supposed to start with the other expression and then differentiate it? Then substitute appropriately to get the above expression