Help Pls with this Q (1 Viewer)

idkkdi

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I get the first two parts. Those are ez. But how would you go about proving the third one? @jimmysmith560 help lol
LHS = (-1)^n
= (1+w)^3n
= RHS

Cancel out the 3nCm, mEZ, 3|m terms.

1/2((Rhs - those terms)x2)
= 1/2 ((3nC1 w+3nC3n-1 w^2) (was w^3n-1) + (3nC2 w+3nC3n-2 w^2) +...... ), for terms higher than w^3, divide by w^3k, kEZ to get either w or w^2
Using part i), and the nCm = nCn-m identity
= 1/2 (-3nC1 - 3nC2 - 3nC4 - 3nC5 .....)
= LHS - those terms
 
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