Hitler's Water Molecule (1 Viewer)

[MysteryGenius]

So I was cleaning out my room and found this question my HSC chemistry teacher had given us as holiday homework lol how nice of her. I don't know if you guys have seen this before, but here you go see if you can answer it. Also, include your working if you can.

Info needed:
- Total volume of water on Earth = 1.3 x 10^9 km^3
-1cm^3 (or 1 mL) of water has the mass = 1g
- Hitler would have weighed 68kg, of which ~66% would have been water
- Standard glass of water = 350mL

How many of the water molecules in the glass of water would have been in Hitler's body?

(I can't believe I still have notes from the HSC around hahaha)

 

[davidbarnes]

So I was cleaning out my room and found this question my HSC chemistry teacher had given us as holiday homework lol how nice of her. I don't know if you guys have seen this before, but here you go see if you can answer it. Also, include your working if you can.



(I can't believe I still have notes from the HSC around hahaha)

All of them, plus a lot more. [logic]

 

[MysteryGenius]

lol No soup for you!

 

[ohexploitable]

How many of the water molecules in the glass of water would have been in Hitler's body?

Can't be both in the glass and inside Hitler's body, so, none. Assuming the glass is outside of him...

 

[davidbarnes]

Can't be both in the glass and inside Hitler's body, so, none. Assuming the glass is outside of him...

Rainman

 

[MysteryGenius]

hahaha I completely forgot about this thread...

Can't be both in the glass and inside Hitler's body, so, none. Assuming the glass is outside of him...

I like the way you think

You have to calculate the fraction of (water molecules in Hitler's body) divided by (the number of water molecules in all the water on Earth) x (number of water molecules in a glass of water).

 

[funnytomato]

calculate the fraction of (water molecules in Hitler's body) divided by (the number of water molecules in all the water on Earth) x (number of water molecules in a glass of water).

= 42

 

[Shadowdude]

I thought this was a Schrodinger's cat question.