MedVision ad

Integration question (1 Viewer)

wilsondw

Member
Joined
Sep 3, 2011
Messages
241
Location
1.6180339887498948482045868343656
Gender
Male
HSC
2012
How do you integrate from 0 to Pi 1/(5-4cosx) dx

It may seem like a silly question

EDIT: problem is that when I use T method...subbing pi into tan(x/2)=tan(pi/2) which is undefined
 
Last edited:

Aysce

Well-Known Member
Joined
Jun 24, 2011
Messages
2,394
Gender
Male
HSC
2012
Let t = tan(x/2)

Differentiate t WRT x to find dx.

So since we let t = tan(x/2), using t-results, we know cos is 1-t^2 over 1+t^2

Follow on from that. I can't use latex :cry:
 

nightweaver066

Well-Known Member
Joined
Jul 7, 2010
Messages
1,585
Gender
Male
HSC
2012
I don't know if you're allowed to do this or not but use infinite as the upper limit after substitution.

It gets you the answer lol.
 

funnytomato

Active Member
Joined
Jan 21, 2011
Messages
848
Gender
Male
HSC
2010
I doubt that's gonna appear in any of your school assessments or the hsc

but it's quite intuitive to understand the idea of an improper integral

this is an example:

in your particular question, we should get(after doing the substitution) :


 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,391
Gender
Male
HSC
2006
You can work your way around the problem using a substitution



The integral then becomes



which allows you to proceed as usual...
 

funnytomato

Active Member
Joined
Jan 21, 2011
Messages
848
Gender
Male
HSC
2010
'You must spread some Reputation around before giving it to Trebla again.'
 

Alkenes

Member
Joined
May 16, 2012
Messages
250
Gender
Undisclosed
HSC
N/A
Guys when we have integration question in which we have to make t=tan(x/2) and we have limits, do we change the limits or just sub the original in the answer?
 

Nooblet94

Premium Member
Joined
Feb 5, 2011
Messages
1,044
Gender
Male
HSC
2012
Guys when we have integration question in which we have to make t=tan(x/2) and we have limits, do we change the limits or just sub the original in the answer?
Either way works, although personally I find changing limits is easier and quicker. Just make sure that if you're not changing limits to evaluate the integral as an indefinite integral first, because if you leave the limits there but make the substitution not only will you confuse yourself, but it's also entirely wrong.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top