# IPT question help (1 Viewer)

#### queenb_3

##### Active Member
Hi everyone,

Could someone help me with the following question please? It's from the 2003 HSC IPT paper. I have no idea if the IPT syllabus has even changed and if this is included in the new syllabus

Thank you!!

#### LegoSlaughter

##### New Member
It involves counting in binary, which I'm pretty sure isn't in this syllabus, but basically:
000 = 0
001 = 1
010 = 2
011 = 3
100 = 4

and so on until it reaches the maximum value for 3 bits which is 111 = 7.
For this question it asks you to take a look at 2, 3 and 4 seconds and it samples it at each dotted point, which correlates to a number for height on the y axis. So you merely convert each value to binary and that's your answer.
At 2 seconds height is 2 so the first value is 010
At 3 seconds height is 4 so the second value is 100
And at 4 seconds height is one so the last value is 001

However I really wouldn't worry about it, I HIGHLY doubt that will be in the exam - nothing to do with sampling and converting to binary anyway. Could be questions on it in the MM topic if you do that.

#### queenb_3

##### Active Member
It involves counting in binary, which I'm pretty sure isn't in this syllabus, but basically:
000 = 0
001 = 1
010 = 2
011 = 3
100 = 4

and so on until it reaches the maximum value for 3 bits which is 111 = 7.
For this question it asks you to take a look at 2, 3 and 4 seconds and it samples it at each dotted point, which correlates to a number for height on the y axis. So you merely convert each value to binary and that's your answer.
At 2 seconds height is 2 so the first value is 010
At 3 seconds height is 4 so the second value is 100
And at 4 seconds height is one so the last value is 001