there is no restriction!question 7 was C, cuz of the restriction on the sin^-1
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there is no restriction!question 7 was C, cuz of the restriction on the sin^-1
im assuming youre talking about 9?there is no restriction!
is that the one where the apex of a cos graph is shifted a bit to the left? i think i got thatim assuming youre talking about 9?
Question 7 was the -asinx +bcosx that was D
correctis that the one where the apex of a cos graph is shifted a bit to the left? i think i got that
it must be q9, and i think A?. I remember i when i solved it, it just going up and down and up and down cuz i just chucked in values outside of -pi and pi, and calc didnt gimme a "MATH ERROR".im assuming youre talking about 9?
Question 7 was the -asinx +bcosx that was D
it was perfectly fine - thats what im saying 9 is Ait must be q9, and i think A?. I remember i when i solved it, it just going up and down and up and down cuz i just chucked in values outside of -pi and pi, and calc didnt gimme a "MATH ERROR".
soooooo....when's the pdf coming alongit was perfectly fine - thats what im saying 9 is A
yeah nah u are right just redid iti got + 1-k i think if thats the issue but idk cant exactly remember, i just got what the q asked
doubt iti got that as well, could it be a mistake on NESAs side
I got a positive which was weird but didn't have enough time to look back on it. You?curious did the newtons law of cooling de have a + or - k?
do you need that tho? thought the question asked you to do it by integratingcurious did the newtons law of cooling de have a + or - k?
ye so i did but didnt know if i needed to specify whether k is negative or positive, ngl first time ive integrated a newtons law of coolingdo you need that tho? thought the question asked you to do it by integrating
my k is negative i think. something like 1/8 ln(3/4)..?And i think i got 39 mins for it to heat to 20 degreesye so i did but didnt know if i needed to specify whether k is negative or positive, ngl first time ive integrated a newtons law of cooling
Yeah I got the samemy k is negative i think. something like 1/8 ln(3/4)..?And i think i got 39 mins for it to heat to 20 degrees
but just solve for k and in the e^kt was it e^kt or e^-ktYeah I got the same
Depends on if you flipped the fraction in the logbut just solve for k and in the e^kt was it e^kt or e^-kt
but wasnt the integral dt/dT = 1/k x 1/T-25 or whatever but 1/k out the front (positive 1/k)Depends on if you flipped the fraction in the log