Math Ext 1 Predictions/Thoughts (1 Viewer)

notme123

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Also, slightly controversial, I quite liked the sample proportion question as it really tested whether you knew your stuff conceptually. Most sample proportion questions are pretty generic just blindly plugging numbers into formulae.
do you think getting the answer of 6000 would be sufficient for 3 marks regardless if we had any errors with inequalities in our working??
 

CM_Tutor

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Looking at the solutions provided above:
  • there is a small error in Q5 where as , but the solution writer has stated that . This is because . Thus, the angle must be obtuse or - the solution writer is correct that NESA have made a mistake in including in the category of "obtuse" angles.
  • In q11(h), though it is not in the syllabus, a potentially simpler solution is:
  • Per the discussion above, q12(a) appears wrong​
  • the handling of the absolute value in q12(b) is wrong as the temperature is increasing towards 25, hence and the equation is where and . The solutions state that and then find , which is a contradiction. They should have and to give .​
  • The resulting equation is better written as so that the term does not appear to be part of the log. Alternatively, it can be written as or as .​
  • For 12(c), the conclusion should be for integers or for .​
  • With q13(b), I wonder if the marking will require a justification that at impact with the wall proves that it has yet to hit the floor...​
  • I am confident that q14(a) is meant to be solved by vectors​
 

tito981

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the wording of the sample size question was so long that i didnt see 'round to the nearest thousand', gonna lose a mark to not rounding imagine that.
 

BAYPALS

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Looking at the solutions provided above:
  • there is a small error in Q5 where as , but the solution writer has stated that . This is because . Thus, the angle must be obtuse or - the solution writer is correct that NESA have made a mistake in including in the category of "obtuse" angles.
  • In q11(h), though it is not in the syllabus, a potentially simpler solution is:

  • Per the discussion above, q12(a) appears wrong​
  • the handling of the absolute value in q12(b) is wrong as the temperature is increasing towards 25, hence and the equation is where and . The solutions state that and then find , which is a contradiction. They should have and to give .​
  • The resulting equation is better written as so that the term does not appear to be part of the log. Alternatively, it can be written as or as .​
  • For 12(c), the conclusion should be for integers or for .​
  • With q13(b), I wonder if the marking will require a justification that at impact with the wall proves that it has yet to hit the floor...​
  • I am confident that q14(a) is meant to be solved by vectors​
Im confused. Is Q12A going up the correct solutions (always above x axis) or going down (below x axis)? which one is the correct answer
 

CM_Tutor

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Im confused. Is Q12A going up the correct solutions (always above x axis) or going down (below x axis)? which one is the correct answer
Assuming that the slope field posted elsewhere in this thread is accurate, the path will have a minimum stationary point and always be above the -axis
 

notme123

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can you still get a scaled mark of 100 if you didnt get 100%? e.g. 69.5 or 69/70
 

icycledough

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can you still get a scaled mark of 100 if you didnt get 100%? e.g. 69.5 or 69/70
Just for clarification, I believe there is no half marks awarded in the HSC, but someone can let me know if they do in fact provide half marks.
 

Trebla

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Just for clarification, I believe there is no half marks awarded in the HSC, but someone can let me know if they do in fact provide half marks.
Converting a mark out of 70 into a mark out of 100 will lead to decimal places.
 

notme123

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Just for clarification, I believe there is no half marks awarded in the HSC, but someone can let me know if they do in fact provide half marks.
its true, my english tutor got half marks for mod c and unseen but idk for maths. probs not.

so you basically get no returns from scaling if you get 69/70. well a 69 is like a 98.6% or something which rounds to 99 ig
 

icycledough

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Like for example, if there was a 1 mark question in a maths exam (not MC), then you would either get 0 or 1 for it; half marks aren't actually awarded in the marking of the exam. Obviously, the percentage conversion will be decimals (like if you get 67,68,69), but the raw mark will be a whole number. I was saying this as for internals for a language I did last year (which involved translation into English), our teacher would deduct a quarter mark for every mistake.
 

Trebla

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A bit out of order.

I've reordered it.

Also part of 12a is missing (direction field on writing paper)

EDIT: 12a picture is here (thanks to pokipoki beanz):

View attachment 33972
Just realised the x and y axes are differently orientated. Is that a typo? Or is that deliberate?
 

tywebb

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Just realised the x and y axes are differently orientated. Is that a typo? Or is that deliberate?
It is not specified in the question that y is a function of x or vice versa. I agree that it's a bit strange. But I don't think it makes any difference.
 

tywebb

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notme123

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for that sample proportion q was it even important that it was less than 2.5?? because every solution ive seen so far doesnt use that fact. i think the z score has to be greater than 2.
 

tito981

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for that sample proportion q was it even important that it was less than 2.5?? because every solution ive seen so far doesnt use that fact. i think the z score has to be greater than 2.
it is important that its less than 2.5, because the question states that 'the sample size is chosen so that the chance of shutting down the machine unnecessarily is less than 2.5%'. So this means since you use z=2, the upper 2.5% will never cause the machine to shut down because it is at the upper end where the machine will never shut down. This is because when you think about p, you want the machine to be in the upper 2.5% because that means it is working to near perfect standard.
 

CM_Tutor

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I doubt it. Here are another set of solutions, by Nash. And you can see they used the same diagram in 12a.
Nash's solution is missing the sketch in q12(d)(iii) and has the sane problem as the other solution in handling the absolute value in q12(b). It does use the vector approach that I believe was sought in q14(a), though.
 

Siwel

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Nash's solution is missing the sketch in q12(d)(iii) and has the sane problem as the other solution in handling the absolute value in q12(b). It does use the vector approach that I believe was sought in q14(a), though.
what about q13a) why is it square root y? thought it should just be y
 

CM_Tutor

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what about q13a) why is it square root y? thought it should just be y
You are correct, and well caught! Nash's solution to q13(a) is indeed incorrect. The solutions posted earlier answered this question correctly. Volumes rotated about the y-axis are indeed of the form


which, in this case of one volume subtracted from another, gives

 

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