Mathematics Thread (2 Viewers)

Jaros · Mar 22, 2026

ChromeDragon26 said:
They overcomplicate to solve as a whole instead of splitting and resolving so idk. The answer is right but it would't fit with the criteria. But then again could it be taken as a different approach? Like other things they will let you deviate from a standard way, (like in adv how you can use mex1 concepts)

yeah but my only concern is my working out is so skimp like barely anything that they might genuinely not give me the marks

alphxreturns · Mar 22, 2026

sry idk how to rotate it

CirrusTheJet · Mar 22, 2026

Great method.

Study to success · Mar 22, 2026

alphxreturns said:
View attachment 52045
sry idk how to rotate it

omg something I can understand. Finally

CirrusTheJet · Mar 22, 2026

Challenging problem involving trigonometry.

alphxreturns · Mar 22, 2026

CirrusTheJet said:
Challenging problem involving trigonometry.

View attachment 52046

turns out to jus be trig formula bashing

CirrusTheJet · Mar 22, 2026

Yep. It's easier than it looks.

C2H6O · Mar 23, 2026

ChromeDragon26 said:
Can I see the working when you are free? I'm genuinely lost

I’m not alph but I gave it a go anyways for the fun of it
$\text{a) }\sin(\theta+\phi)=n\sin\theta\sin\phi$
$\sin\theta\cos\phi+\cos\theta\sin\phi=n\sin\theta\sin\phi$
$1+\frac{\tan\phi}{\tan\theta}=n\tan\phi \,(\text{divide both sides by}\sin\theta\cos\phi)$
$1=\tan\phi\left( n-\frac1{\tan\theta} \right)$
$\tan\phi=\frac{1}{n-\frac{\cos\theta}{\sin\theta}}$
$\tan\phi=\frac{\sin\theta}{n\sin\theta-\cos\theta} \text{ Q.E.D}$

$\text{b) }\tan\phi=\frac{\sin\frac{\pi}4}{2\sin\frac\pi4-\cos\frac\pi4}$
$=\frac{\frac{\sqrt2}2}{2\frac{\sqrt2}2-\frac{\sqrt2}2}$
$=\frac{\frac{\sqrt2}2}{\frac{\sqrt2}2}$
$=1$

$\text{c) }\theta=\phi$
$\sin(\theta+\phi)=n\sin\theta\sin\phi$
$\sin2\theta=n\sin^2\theta$
$2\sin\theta\cos\theta=n\sin^2\theta$
$4\sin^2\theta\cos^2\theta=n^2\sin^4\theta$
$4\cos^2\theta=n^2(1-\cos^2\theta)$
$\cos^2\theta(4+n^2)=n^2$
$\cos\theta=\frac n{\sqrt{n^2+4}} \, (0<\theta<\frac \pi 2, n>1) \, \text{Q.E.D.}$

alphxreturns · Mar 23, 2026

C2H6O said:
I’m not alph but I gave it a go anyways for the fun of it
$\text{a) }\sin(\theta+\phi)=n\sin\theta\sin\phi$
$\sin\theta\cos\phi+\cos\theta\sin\phi=n\sin\theta\sin\phi$
$1+\frac{\tan\phi}{\tan\theta}=n\tan\phi \,(\text{divide both sides by}\sin\theta\cos\phi)$
$1=\tan\phi\left( n-\frac1{\tan\theta} \right)$
$\tan\phi=\frac{1}{n-\frac{\cos\theta}{\sin\theta}}$
$\tan\phi=\frac{\sin\theta}{n\sin\theta-\cos\theta} \text{ Q.E.D}$

$\text{b) }\tan\phi=\frac{\sin\frac{\pi}4}{2\sin\frac\pi4-\cos\frac\pi4}$
$=\frac{\frac{\sqrt2}2}{2\frac{\sqrt2}2-\frac{\sqrt2}2}$
$=\frac{\frac{\sqrt2}2}{\frac{\sqrt2}2}$
$=1$

$\text{c) }\theta=\phi$
$\sin2\theta=n\sin^2\theta$
$2\sin\theta\cos\theta=n\sin^2\theta$
$4\sin^2\theta\cos^2\theta=n^2\sin^4\theta$
$4\cos^2\theta=n^2(1-\cos^2\theta)$
$\cos^2\theta(4+n^2)=n^2$
$\cos\theta=\frac n{\sqrt{4+n^2}} \, (0<\theta<\frac \pi 2, n>1) \, \text{Q.E.D.}$

haha i was just getting to uploading it. thx for a better explanation

C2H6O · Mar 23, 2026

alphxreturns said:
View attachment 52047
haha i was just getting to uploading it. thx for a better explanation

your ones are lowkey cleaner im rusty as hell so I was kinda brute forcing it by isolating whatever term on one side before cleaning up the rest

CirrusTheJet · Mar 23, 2026

Why are permutations so difficult? Now I have to delay my Mathematics Extension I (extended through term 1) topic completion by one day.

f7eeting · Mar 23, 2026

CirrusTheJet said:
Why are permutations so difficult? Now I have to delay my Mathematics Extension I (extended through term 1) topic completion by one day.

what are you finding difficult about them?

CirrusTheJet · Mar 23, 2026

I don't know, the questions just mess with my head. I will look more into it tomorrow I guess.

CirrusTheJet · Mar 23, 2026

I did see pascal's triangle, factorials and other stuff - which aren't too hard I think. I jus t want to relearn my weak topics while I'm at it so bI am also prepared for MATH1231 just in case.

RZ1234 · Mar 23, 2026

they are very hard. i learnt factoreals in OC class

RZ1234 · Apr 1, 2026

CirrusTheJet said:
I thought I was actually going to fail, but only just managed to get 20/20. MATH1131 workload is so large, it's actually like 3 courses on its own.

bro math1131 is basically primary school maths. Math55 at Harvard is actually like 3 courses on its own

CirrusTheJet · Apr 6, 2026

Interesting projectile motion problem.

Jaros · Apr 6, 2026

here is my solution:

CirrusTheJet · Apr 6, 2026

Great!

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