Hudz777
Member
- Joined
- Jul 29, 2023
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- 84
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- HSC
- 2023
I couldn’t get i) but i got ii). just said |b| = b.b. and expanded lhs and rhs and they equaled. was hella working but yeahyall know how on earth to do 15b ii?
I couldn’t get i) but i got ii). just said |b| = b.b. and expanded lhs and rhs and they equaled. was hella working but yeahyall know how on earth to do 15b ii?
oh mother truckerrrthe r(t) function is for both up and down coz its displacement from origin, not dist covered
I didn’t have time to expand part ii and stuff rip but part i was ez for meI couldn’t get i) but i got ii). just said |b| = b.b. and expanded lhs and rhs and they equaled. was hella working but yeah
YES I LOVE YOUit was 5pi for the period right
When you handle the double angle with a substitution your limits would change from 0 to pi. However, note that integrating a sine function (and subsequently it’s powers) from 0 to pi is the same as twice that from 0 to pi/2 by symmetry (see the graph). You can show this algebraically but that’s the rough idea of it.@Trebla can you explain 15.a)ii)
ayee sameI just fully expanded the LHS and RHS separately (like LHS=… RHS=…) which then showed that LHS=RHS
nope they are the same lineaye anyone get q5? c right?
no they arent, how???nope they are the same line
They are they pass through same point and direction vector differ by scalarno they arent, how???
solve for intersectionno they arent, how???