d/dx(x ln x)=x(1/x)+lnx(1)kido_1 said:oh, ok, thanx.
Find the derivative of x In x.
=1+lnx
Next Question (last question in my 2u assessment today ):
Find the equation of the parabola with vertex (3,13) and a y-intercept of 4.
d/dx(x ln x)=x(1/x)+lnx(1)kido_1 said:oh, ok, thanx.
Find the derivative of x In x.
y = ax2+bx+cRiviet said:d/dx(x ln x)=x(1/x)+lnx(1)
=1+lnx
Next Question (last question in my 2u assessment today ):
Find the equation of the parabola with vertex (3,13) and a y-intercept of 4.
Riviet said:d/dx(x ln x)=x(1/x)+lnx(1)
=1+lnx
Next Question (last question in my 2u assessment today ):
Find the equation of the parabola with vertex (3,13) and a y-intercept of 4.
Can't you just solve simulataneously???kido_1 said:The line y= 71x-315 is a tangent to the curve y=14x^2+17x+13.
Find the point of contact.
possiblyYBK said:Can't you just solve simulataneously???
71x-315 = 14x^2+17x+13
...........
lol, those numbers are hugekadlil said:possibly
oh well, I got the answer
Yeh, the question seems made up like on the spotYBK said:lol, those numbers are huge
Haha same here, didn't have time to find the pof's, we only had 45 mins and this question was 1 of 2... the other was a hard parametrics question.insert-username said:Can't be bothered find f''(x)