P
pLuvia
Guest
Easier way
That should be right
∫x(x2+1)3 dx
Let u = x2+1
du = 2x dx
du/2 = xdx
I = ∫ 1/2 u3 du
= 1/2 [ u4/4] + C
= 1/8 (x2+1)4 + C
Let u = x2+1
du = 2x dx
du/2 = xdx
I = ∫ 1/2 u3 du
= 1/2 [ u4/4] + C
= 1/8 (x2+1)4 + C
That should be right