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MX2 Marathon (1 Viewer)

ExtremelyBoredUser

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nah i'm a queen 💅
Interdice, this is a man. Yes he is asian but he is not japanese or korean, I can confirm from personal experience, you might be a dwarf in comparison however like a pitbull I am worried you might try to slober all over him. He is a hard working person and has a family to take care of, please do not s** assault this man when you get on UNSW campus, he is simply making a very ironic and funny joke which juxtaposes my claim that he is a king to seem zesty, this does not warrant any abuse.

Much appreciated,
A worried friend of Lith_30
 

HazzRat

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for question (iii) here, where did they get the first statement of the proof from? I could solve the question after getting that statement but like idk where they got it
jnjanwfjwan.PNG
 

liamkk112

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View attachment 42394

for question (iii) here, where did they get the first statement of the proof from? I could solve the question after getting that statement but like idk where they got it
View attachment 42395
in ii) let a^3 = (a^3/1+a^3), b^3 = (b^3 /1+b^3), c^3 = (1/1+c^3) for the first one.
then taking cube roots to get a,b and c u see how the rhs comes about
 

liamkk112

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though i'm not sure what the motivation is for thinking of that specific substitution
 

HazzRat

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For question (ii) here, y is the angle ∠OAC a right angle? I kinda assumed ∠OCA to be the right angle

brgefqwd.PNG
 

Luukas.2

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View attachment 42402
For question (ii) here, y is the angle ∠OAC a right angle? I kinda assumed ∠OCA to be the right angle

View attachment 42403
The right angle is definitely OAC as the tangent to a circle is always perpendicular to the radius at the point of contact.

If OCA was a right angle, then the tangent at A would be parallel to OC and thus OA would not be a tangent, but rather would cross the circle at some point B between O and A... in which case, there must be points on the circle between A and B with a larger principal argument.

 

HazzRat

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solid induction question from my school's 2020 test
 

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