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My answers (not including long response) (1 Viewer)

M@ster P

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umm 24b?

I got m between 1 and 3, because directly proportional means it is a straight line, and a straight line occurs between 1 and 3

Edit: when i think about it know directly proportional could mean anything, y = x^3, x^4 not just y =x, so not sure now
 
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Macdwg

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I'm going to say that the magnet question is open to interpretation, it really depends on the distance between the magnet and the wire, which we aren't given, and hence from this you are unable to assume that the field lines are acting horizontally like moke is suggesting, nor are you able to assume that its far enough for the field lines to pull back in the direction of the south pole. My guess is that you probably should assume they are acting horizontally to the right, however it's arguable.

Hence why this question sucks penis, the end.
 

Ruptured

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umm 24b?

I got m between 1 and 3, because directly proportional means it is a straight line, and a straight line occurs between 1 and 3

Edit: when i think about it know directly proportional could mean anything, y = x^3, x^4 not just y =x, so not sure now
Directly propertional is where the ratio between the two values is constant. So just a straight line of any gradient
 

darkchild69

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umm 24b?

I got m between 1 and 3, because directly proportional means it is a straight line, and a straight line occurs between 1 and 3

Edit: when i think about it know directly proportional could mean anything, y = x^3, x^4 not just y =x, so not sure now
Directly proportional means y = kx where k is a constant of proportionality, hence plotting y vs x will be a straight line.

not y = kx^2 (this means y is directly proportional to x^2, not x. If you plot y vs x in this form, it will not be a straight line, hence not directly proportional)

mass should be between around 1.3-3

It is definately not 1-3, it begins after 1
 

M@ster P

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Directly proportional means y = kx where k is a constant of proportionality, hence plotting y vs x will be a straight line.

not y = kx^2 (this means y is directly proportional to x^2, not x. If you plot y vs x in this form, it will not be a straight line, hence not directly proportional)

mass should be between around 1.3-3

It is definately not 1-3, it begins after 1
sigh, wasn't accurate enough
 

youngminii

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Directly proportional means y = kx where k is a constant of proportionality, hence plotting y vs x will be a straight line.

not y = kx^2 (this means y is directly proportional to x^2, not x. If you plot y vs x in this form, it will not be a straight line, hence not directly proportional)

mass should be between around 1.3-3

It is definately not 1-3, it begins after 1
1.3 - 3?
It was straight from 0 - 1.3, then became all wavy from 1.3 - 3.. Unless I remember wrong? Damn
 

darkchild69

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1.3 - 3?
It was straight from 0 - 1.3, then became all wavy from 1.3 - 3.. Unless I remember wrong? Damn
Shit yeah, i think you are right actually!

Damn paper is upstairs now, cbf checking, but im pretty sure you are right
 

Ruptured

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Shit yeah, i think you are right actually!

Damn paper is upstairs now, cbf checking, but im pretty sure you are right
Glad to hear that because I was thinking a minute ago that I could've sworn it was 0-1.3
 

darkchild69

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LoL

I REALLY need to read the questions before I answer

I'm meant to know this stuff!

I just checked the paper and yep, definately 0-1.3 :D
 

fallingstar

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Also, anyone who got A=34.5 is wrong and made this mistake.
I x I does not = 2I, it equals I squared. Therefore your answers were 69/2 = 34.5A when they should have been root 69 = 8.3A
dammit i did this! I'm an idiot, why can't I do basic math?!?!?
argh
 

tommowhit

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thas a conventinal current

n normal electric current (electron flow) they travel from negative to positive
u use the right hand in the right hand palm rule for convenionl current if ur going 2 use electron flow u still use direction of positive charge or use left hand
 

whitnall8

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We always deal in conventional current though, not in the flow of electrons.
 

tashisthebest

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umm no you still uses your right hand rule for a electric current

all the past papers n question i have done i have used the right hand rule n i have been right.

i have been taught this by ma teacher n my tutor.

so im sure about this
 

random-1005

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i did both to be sure!


I was almost ready to write on the paper: Thanks for giving us engineering students an unfair advantage!
But they look noting like conventional stress/strain curves!
they practically held your hand with that rubber band question.

lol, the questions people are asking, you are all shit, why did u even do physics, just roll over and die noobs
 
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