eyeseeyou
Well-Known Member
Oh shit my conditionYou needed to take the negative square root, since y needed to be ≤ 2.
y=squareroot of (x) +2, y<_2
wait wtf...
Oh shit my conditionYou needed to take the negative square root, since y needed to be ≤ 2.
When you took the square root, why did you choose the positive and not the negative one? Think about which one makes sense given the condition imposed.Oh shit my condition
y=squareroot of (x) +2, y<_2
wait wtf...
idk this is pissing me offWhen you took the square root, why did you choose the positive and not the negative one? Think about which one makes sense given the condition imposed.
Read what he said again. He clearly said think about which one makes sense given the condition imposedidk this is pissing me off
Show me your working out Trebla
BTW you should be a tutor Trebla
You won't learn if I just spoonfeed you the answer.idk this is pissing me off
Show me your working out Trebla
BTW you should be a tutor Trebla
In the bolded part, why did you pick only the positive square root? Why did you ignore/reject the negative square root?I'll try it here
y=(x-2)^2, x <_ 2
Switch x and y around
x=(y-2)^2, y <_ 2
Squareroot of x=y-2, x <_2
squareroot of x+2=y
y=squareroot of (x) +2
Given our condition is x <_2 we can only have one case
Okay wtf am I doing wrong
Get carrotsticks to help us out
The condition is wrong, it's y<_2You won't learn if I just spoonfeed you the answer.
In the bolded part, why did you pick only the positive square root? Why did you ignore/reject the negative square root?
Your working is fine except that one part. If you actually tried to answer my question you will be able to understand why.The condition is wrong, it's y<_2
Also it's not really spoonfeeding me if I do the question and get it wrong and someone shows me how to do it correctly
First or second question in my quote?Your working is fine except that one part. If you actually tried to answer my question you will be able to understand why.
BothFirst or second question in my quote?
A derivation based on the unit circle may be found in the Year 11 3U Pender (Cambridge) textbook.Where are the following formulas derived from:
1. sin(a+b)=sinacosb+sinbcosa
2. sin(a-b)=sinacosb-sinbosa
3. cos(a+b)=cosacosb-sinasinb
4.cos(a-b)=cosacosb+sinasinb
5. tan(a+b)=(tana+tanb)/(1-tanatanb)
6. tan(a-b)=(tana-tanb/1+tanatanb)
Why don't you prove them yourself.Where are the following formulas derived from:
1. sin(a+b)=sinacosb+sinbcosa
2. sin(a-b)=sinacosb-sinbosa
3. cos(a+b)=cosacosb-sinasinb
4.cos(a-b)=cosacosb+sinasinb
5. tan(a+b)=(tana+tanb)/(1-tanatanb)
6. tan(a-b)=(tana-tanb/1+tanatanb)
Pls answer my questionIn the bolded part, why did you pick only the positive square root? Why did you ignore/reject the negative square root?
The double angle formulas follow by letting a = b in each of the trig. expansion identities for f(a+b).What about the double angle formula for Tan:
tan2(theta)=2tan(theta)/1-tan^2(theta)
Bumping and liking this because you need to stop ignoring Trebla @ eyeseeyou.Pls answer my question
See the 2U/3U syllabus or a textbook for the derivationWhere are the following formulas derived from:
1. sin(a+b)=sinacosb+sinbcosa
2. sin(a-b)=sinacosb-sinbosa
3. cos(a+b)=cosacosb-sinasinb
4.cos(a-b)=cosacosb+sinasinb
5. tan(a+b)=(tana+tanb)/(1-tanatanb)
6. tan(a-b)=(tana-tanb/1+tanatanb)
Well the answer to that question is yes, just expand out the RHSWhat about product to sum
2sinAcosB=sin(A+B)+sin(A-B)
Do you just expand this out?
Yeah.What about product to sum
2sinAcosB=sin(A+B)+sin(A-B)
Do you just expand this out?