JamiL
Member
- Joined
- Jan 31, 2004
- Messages
- 704
- Gender
- Male
- HSC
- 2005
the 2u class jus started it last term so u should have started it but i believe his class hasn't
y=e^xsin2x we have
y=e^u where u is a function
ie dy/dx=dy/dx(u)*e^u
therefore dy/dx= dy/dx(xsin2x)*e^xsin2x
= (sin2x + xcos2x)*e^xsin2x
got the same answer but mine was easyer to do... lol
y=e^xsin2x we have
y=e^u where u is a function
ie dy/dx=dy/dx(u)*e^u
therefore dy/dx= dy/dx(xsin2x)*e^xsin2x
= (sin2x + xcos2x)*e^xsin2x
got the same answer but mine was easyer to do... lol