Preliminary mathematics marathon (1 Viewer)

[SpiralFlex]

Prove
(sin 150 + cos 270 + tan 315 )^2= sin^2 135 cos^2 225

Just wondering is there are faster method then finding the values of both sides then comparing ?

Don't think so, either way, you would still need to convert.

 

[Saturn WY15]

Yeah, that's what i thought.

Thanks Anyway Spi

 

[SpiralFlex]

Yeah, that's what i thought.

Thanks Anyway Spi

Actually, let me think about that.

 

[Saturn WY15]

Hey Spi, Can u do this question

Solve the equation 6x^4-29x^3+40x^2-7x-12=0, given the product of two of the roots being 2?

Cheers

 

[Trebla]

I'm pretty sure you mean
In that case:

Solving gives
(Discard negative root of quadratic)

Golden ratio

 

[The Derivative]

 

[SpiralFlex]

Mario is delicious.

 

[The Derivative]

Mario is delicious.

Can you do it, Spi?

 

[The Derivative]

I will rep whoever can answer this. K,go.

 

[SpiralFlex]

I will rep whoever can answer this. K,go.

Oh you are being serious. Sorry, I just came back from watching the Swans game. I'll attempt it now. Is this a trick question?

 

[slyhunter]

 

[SpiralFlex]

So Mario does survive after all.

 

[Gigacube]

I will rep whoever can answer this. K,go.

That is the best maths problem I have ever seen.

 

[The Derivative]

BOSS. :')

So Mario does survive after all.

~Theoretically.

That is the best maths problem I have ever seen.

Why can't all maths questions be like this? RELEVANT TO LIFE?
I'd happily do my math homework/exams etc.

 

[SpiralFlex]

BOSS. :')

~Theoretically.

Why can't all maths questions be like this? RELEVANT TO LIFE?
I'd happily do my math homework/exams etc.

Where did you get this question?

 

[The Derivative]

Where did you get this question?

From tumblr.

 

[Timothy.Siu]

Golden ratio

Find the value of

 

[Hermes1]

Find the value of

thats cool, what is the golden ratio? and do you learn it in uni?

 

[Hermes1]

Find the value of

and then cross multiplying and solving you get:

x = (1 + root5)/2 or (1 - root 5)/2

and then you take the positive one?

is that right?

 

[Timothy.Siu]

and then cross multiplying and solving you get:

x = (1 + root5)/2 or (1 - root 5)/2

and then you take the positive one?

is that right?

yep, u can do it like that, but the more obvious way i thought was to say


well done.

thats cool, what is the golden ratio? and do you learn it in uni?

Just read the wiki http://en.wikipedia.org/wiki/Golden_ratio
I haven't learnt it in uni, although it comes up sometimes, like in that above "continued fraction" representation of the golden ratio.