Projectile Question (1 Viewer)

lilly luta

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A bundle of fireworks is launched from Centrepaint Tower in Sydney, 305m above the ground. It is launched with a valocity of 45m/s at an angle of 30 degree above the horizontal. the fireworks explode at a safe height of 280m above the groud.

a/ What is the initial vertical component of the velocity? (I got that)
b/ What is the maximum heiht reached by the fireworks before they explode? (Got this too :)
c/How long after the launch do the fireworks explode?
d/ What is the horizontal distance from the tower to the fireworks when they explode?

Please help me with c and d :) thanks a lot
 

qrpw

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Consider the vertical part of the initial velocity found in Part A. We can use that, plus a=-9.8 and s=-25m (the distance it travels before it explodes, negative since it is closer to the ground) to find time. I'm sure you can work out which formula to use.
For D just use the time of flight and horizontal velocity.
 

qrpw

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The fireworks are launched 305m above the ground, and explode 280m above the ground. So in essence, it has travelled -25m vertically (considering up is positive).
 

SpiralFlex

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A)




[HR][/HR]

B)








[HR][/HR]

C)

So,


















[HR][/HR]

D)



 
Last edited:

SpiralFlex

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^Vids old, you 2013ers haven't seen it yet because you weren't around at our time.
 

nightweaver066

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hey spiral why is it in part b u made Vy = 0?
At maximum height, i.e. the point at which it's not moving up or down (kind of like the maximum turning point of a parabola), the vertical velocity is 0 (Vy = 0).
 

SpiralFlex

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At maximum height the vertical component of velocity is zero.
 

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