Question in math adv test that cost me my grade since idk how to do it (1 Viewer)

jane1820

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damn your teacher's tough to please
I mean everyone in the 25 cohort who did ext 1 math failed (but one accelerated who got 90%) (everyone dropped but the two accelerated kids one of whom failed)
more than half of the 25 adv cohort failed advanced math
No one of the 25 cohort is doing ext 2 math

so this yr the math faculty went crazy and are bitches
 

killer queen

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The teacher said its our fault if we didnt know how to solve it bc it means (and i quote) ‘you cant apply your previous knowledge to new concepts’ which in one way or another i agree
like...she isn't wrong...but the question to me seems really clearly designed to separate like band 5s from band 6s and high band 6s and there's bound to be questions like that, and the whole point is that they're a challenge

so she's stating the obvious in a way that to me is kinda pointless and isn't really conducive to anything
 

cristal

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I mean everyone in the 25 cohort who did ext 1 math failed (but one accelerated who got 90%) (everyone dropped but the two accelerated kids one of whom failed)
more than half of the 25 adv cohort failed advanced math
No one of the 25 cohort is doing ext 2 math

so this yr the math faculty went crazy and are bitches
Damnnn
I did much much better in my MX1 test than advanced 💀 💀 💀
 

Sorghum Sneedley

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no i think the punctuation is wrong
i think they want k to have no real solutions

wait no its of
no wonder they never became english teachers
i think it can be interpreted as "when is m equal for y = mx + c for c1 doesn't equal to c2" when they are both in gradient intercept form. So there will be no real solutions of intersection
 
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Hehehe22

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Wow I missed the party but this question is pretty difficult... first thing that came to my mind was making it into a quadratic and using the discriminant (which is the typical method for these kinds of questions) but all your solutions are really enlightening
 

alphxreturns

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theres a hint in the question: they tell u that they're linear equations.
usually 2 linear equations (aka lines) intersect once - 1 solution
but to get 0 real solutions they must thus not intersect at all i.e. they are parallel lines with different y intercepts
so just rearrange the equations into gradient intercept form and equate the gradients
certified best method (working 2025) (unpatched)


soooo 4/3 is the only solution? the teacher is wrong? omg
 

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