jane1820
Well-Known Member
Uh this is advanced thoit’s much quicker to use coefficient matrix
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Uh this is advanced thoit’s much quicker to use coefficient matrix
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damn your teacher's tough to pleaseThe teacher said its our fault if we didnt know how to solve it bc it means (and i quote) ‘you cant apply your previous knowledge to new concepts’ which in one way or another i agree
this aint even in ext 2 (anymore)Uh this is advanced tho
I mean everyone in the 25 cohort who did ext 1 math failed (but one accelerated who got 90%) (everyone dropped but the two accelerated kids one of whom failed)damn your teacher's tough to please
like...she isn't wrong...but the question to me seems really clearly designed to separate like band 5s from band 6s and high band 6s and there's bound to be questions like that, and the whole point is that they're a challengeThe teacher said its our fault if we didnt know how to solve it bc it means (and i quote) ‘you cant apply your previous knowledge to new concepts’ which in one way or another i agree
joined 2003??? wowit’s much quicker to use coefficient matrix
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DamnnnI mean everyone in the 25 cohort who did ext 1 math failed (but one accelerated who got 90%) (everyone dropped but the two accelerated kids one of whom failed)
more than half of the 25 adv cohort failed advanced math
No one of the 25 cohort is doing ext 2 math
so this yr the math faculty went crazy and are bitches
what the flippity flop is thatit’s much quicker to use coefficient matrix
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i said before it is determinant method which is much more efficientwhat the flippity flop is that
when did/do we learn thisi said before it is determinant method which is much more efficient
whenever your teacher decides to teach you properlywhen did/do we learn this
i never had to learn i think it its oos now (might have used to be in the old syllabus) unless this is just another thing my teacher didnt teach me for some reasony'all I thought matrices were like some niche math ext 2 vectors knowledge
i think it can be interpreted as "when is m equal for y = mx + c for c1 doesn't equal to c2" when they are both in gradient intercept form. So there will be no real solutions of intersectionno i think the punctuation is wrong
i think they want k to have no real solutions
wait no its of
no wonder they never became english teachers
nigga this is hsc math, and advanced to be specific.it’s much quicker to use coefficient matrix
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i love u, will use oos methods in my next examit’s much quicker to use coefficient matrix
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certified best method (working 2025) (unpatched)theres a hint in the question: they tell u that they're linear equations.
usually 2 linear equations (aka lines) intersect once - 1 solution
but to get 0 real solutions they must thus not intersect at all i.e. they are parallel lines with different y intercepts
so just rearrange the equations into gradient intercept form and equate the gradients