Random log question (1 Viewer)

[enigma_1]

How do I find "r" using logs for this:

r^5=32 ??

 

[Trebla]

You don't need logs?

 

[integral95]

You simply take the 5th root of both sides

You don't need to use logs it's only in questions like

You use logs when the index is the variable basically

 

[enigma_1]

Ohhhh ok thank you - I think that was a hole in my knowledge :L

 

[williamdaft]

You just take the 5th root of both sides and you get r=2.

But if the question was 5^r = 32, you can use log.
log(5^r) = log32
r x log5 = log32
Thus, r = (log32)/(log5) approximately = 2.15338279.