Kurwa
Member
quadratic equations and finding fractions.
That is full of shit.Integration < Volumes < Mechanics < polynomials < complex numbers < conics < Harder 3 unit < graphs
ii)
let conjugate be cw
(cw)^4 + 2(cw)^3 + 3(cw)^2 + 2(cw) + 1 = c(w^4+2w^3+3w^2+2w+1) = c(0) = 0
wait wait
that one does not have a c, so factorising c out does not make one bit of sense
so what u r saying wbar = cw, okay fine that makes sense
then u are factorising c out of the equation ....... that is not possible.
think about it, so what bacchus is basically saying ... (wbar)^4 + 2 (wbar)^3 ........
then if u are factorising c out of the equation, u are saying bar( w^4 + 2w^3 ....... )
u cant factorise bar out
someone please explain, what he is doing......because it does not make sense
thanks
welll 1 = c(1)ii)
let conjugate be cw
(cw)^4 + 2(cw)^3 + 3(cw)^2 + 2(cw) + 1 = c(w^4+2w^3+3w^2+2w+1) = c(0) = 0
wait wait
that one does not have a c, so factorising c out does not make one bit of sense
so what u r saying wbar = cw, okay fine that makes sense
then u are factorising c out of the equation ....... that is not possible.
think about it, so what bacchus is basically saying ... (wbar)^4 + 2 (wbar)^3 ........
then if u are factorising c out of the equation, u are saying bar( w^4 + 2w^3 ....... )
u cant factorise bar out
someone please explain, what he is doing......because it does not make sense
thanks
when i did that question above, i just couldn't be bothered to write c(1), so ye.
my answer still holds